To calculate mean: Just add up all the numbers, then divide by how many numbers there are.345 + 673 + 728 +775 + 822 +827 +839 + 951 = 5960/8 = 745
633 + 673 + 728 +775 + 822 +827 +839 + 951 = 6248/8 = 781781- 745 = 35 It increases by 35To find the Median, place the numbers in value order and find the middle. BUT, with an even amount of numbers things are slightly different. In that case we find the middle pair of numbers, and then find the value that is half way between them. This is easily done by adding them together and dividing by two. 345 673 728 775 822 827 839 951 The median = 822-775 /2
The median =23.5After the change633 673 728 775 822 827 839 951 The median = 822-775 /2
The median =23.5The median stays the same.
Answer:
t = 2.52 seconds
Step-by-step explanation:
h=139-15t-16t^2
We want to know when the ball hits the ground
That would be when h=0
0 = 139-15t-16t^2
We can use the quadratic formula to find t
t = -b ± sqrt(b^2-4ac)
----------------------
2a
where a = -16 b = -15 and c = 139
t = -(-15) ± sqrt((-15)^2-4(-16)139)
----------------------
2(-16)
t = (15) ± sqrt(225+8896)
----------------------
-32
t = (15) ± sqrt(9121)
----------------------
-32
t = 15+ sqrt(9121) t = 15- sqrt(9121)
-------------------- or -------------------
-32 -32
-3.453247707 or 2.515747707
Since time cannot be negative
2.515747707
Round to the nearest hundredth
t = 2.52 seconds
Here we must see in how many different ways we can select 2 students from the 3 clubs, such that the students <em>do not belong to the same club. </em>We will see that there are 110 different ways in which 2 students from different clubs can be selected.
So there are 3 clubs:
- Club A, with 10 students.
- Club B, with 4 students.
- Club C, with 5 students.
The possible combinations of 2 students from different clubs are
- Club A with club B
- Club A with club C
- Club B with club C.
The number of combinations for each of these is given by the product between the number of students in the club, so we get:
- Club A with club B: 10*4 = 40
- Club A with club C: 10*5 = 50
- Club B with club C. 4*5 = 20
For a total of 40 + 50 + 20 = 110 different combinations.
This means that there are 110 different ways in which 2 students from different clubs can be selected.
If you want to learn more about combination and selections, you can read:
brainly.com/question/251701
Answer:
C. 91.46
Step-by-step explanation:
Use BODMAS!
Answer: x=-4.8
Step-by-step explanation:
Given
-10x+4=52
Subtract 4 on both sides
-10x+4-4=52-4
-10x=48
Divide -10 on both sides
-10x/-10=48/-10
x=-4.8
Hope this helps!! :)
Please let me know if you have any questions
