3 years ago

How many three-letter sequences are possible that use the letters q,u,a,k,e,s at most once each?

1 answer:

8 0

6P3 => 6!/(6-3)! = 120.

I can't very well explain, but I hope it works.

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Bumek [7]

Answer:

Step-by-step explanation:

$\frac{b}{-3}+4< 13$

Step 1: Subtract 4 form both sides

Step 2: Multiply both sides by (-3). when we are multiplying by (-3) the < will change to >.

$\frac{b}{-3}+4-4 9*-3\\\\b > -27$

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trasher [3.6K]

Answer:

F, M, and J.

Step-by-step explanation:

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JulijaS [17]

It’s F the first one

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Sholpan [36]

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It's 6.

Step-by-step explanation:

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geniusboy [140]

Answer:

6(4.75+x)

Step-by-step explanation:

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