A.
2/3A=-24
time both sides by 3/2
A=-72/2
A=-36
B.
20=-B/0.2
times both sides by 0.2
4=-B
times -1
-4=B
distance between 2 points x and y is |x-y|
so
distance between A and B is distance between -4 and -72 or
|-72-(-4)|=|-72+4|=|-68|=68
the distance is 68
Answer:
m=-15
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable. m=-15
<em>Greetings from Brasil...</em>
In a trigonometric function
F(X) = ±UD ± A.COS(Px + LR)
UD - move the graph to Up or Down (+ = up | - = down)
A - amplitude
P - period (period = 2π/P)
LR - move the graph to Left or Right (+ = left | - = right)
So:
A) F(X) = COS(X + 1)
standard cosine graph with 1 unit shift to the left
B) F(X) = COS(X) - 1 = -1 + COS(X)
standard cosine graph with 1 unit down
C) F(X) = COS(X - 1)
standard cosine graph with shift 1 unit to the right
D) F(X) = SEN(X - 1)
standard Sine graph with shift 1 unit to the right
Observing the graph we notice the sine function shifted 1 unit to the right, then
<h3>Option D</h3>
<em>(cosine star the curve in X and Y = zero. sine start the curve in Y = 1)</em>