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blsea [12.9K]
3 years ago
9

The ratio of the present age of mother and daughter is 3:1. Six years ago the ratio of their age was 6 : 1. Find their present a

ge.​
Mathematics
1 answer:
bezimeni [28]3 years ago
5 0

Answer:

30 and 10

Step-by-step explanation:

Given ratio of age = 3 : 1 = 3x : x ( x is a multiplier )

Six years ago their age ratio was

3x - 6 : x - 6 = 6 : 1 ← express in fractional form

\frac{3x-6}{x-6} = \frac{6}{1} ( cross- multiply )

6(x - 6) =3 x - 6

6x - 36 = 3x - 6 ( subtract 3x from both sides )

3x - 36 = - 6 ( add 36 to both sides )

3x = 30 ( divide both sides by 3 )

x = 10

Thus their present ages are

mother = 3x = 3 × 10 = 30

daughter = x = 10

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Answer:

Any line with the slope of 2/3 would be perpendicular.

Step-by-step explanation:

To find this, first solve the equation for y.

-2y = 3x + 7

y = -3/2x - 7/2

Perpendicular lines always have opposite and reciprocal slopes. Therefore, we flip the slope in the original equation (-3/2 becomes -2/3) and then we change the sign (-2/3 becomes 2/3)

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Step-by-step explanation:

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