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ArbitrLikvidat [17]
3 years ago
10

Just some questions I need answered! Solve 4z > -6 Solve x + 19 <= -5

Mathematics
1 answer:
Dmitriy789 [7]3 years ago
7 0

4z>-6

divide by 4

z>-6/4

z>-3/2



x+19<= -5

subtract 19 from both side

x<= -24


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\bf \textit{parabola vertex form with focus point distance} \\\\ \begin{array}{llll} 4p(x- h)=(y- k)^2 \\\\ 4p(y- k)=(x- h)^2 \end{array} \qquad \begin{array}{llll} vertex\ ( h, k)\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=-5\\ k=7\\ p=-2 \end{cases}\implies 4(-2)[x-(-5)]=[y-7]^2 \\\\\\ -8(x+5)=(y-7)^2\implies x+5=\cfrac{(y-7)^2}{-8}\implies \boxed{x=-\cfrac{1}{8}(y-7)^2-5}

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