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horsena [70]
3 years ago
5

A city planner is mapping out some new features for a triangular park. She sketches the park on grid paper. The coordinates of t

he vertices of the park are (1, 1), (1, 4), and (−3, 4).
The city planner wants to put recycling bins at the circumcenter of the park. What are the coordinates of the recycling bins?
Mathematics
2 answers:
ivann1987 [24]3 years ago
7 0

Answer:

Step-by-step explanation:

hgfdsdfghjklp;polkjhgfdfghjkl;lkjhgf

valentinak56 [21]3 years ago
5 0

Answer:

The area of the triangle enclosed by the three points

A(1,1), B(1,4) and C(-3,4) in this question will be given by

|Ax ( By − Cy)+ Bx(Cy−Ay)+ Cx(Ay− By) |/2

=|1(4-4)+1(4-1)+-3(1-4)|/2=10/5= 5 sq. units

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Anne deposited $500 in an account that earns 6% simple annual interest. Shelly deposited $500 in an account that earns 6% annual
Inga [223]

Answer:

It is clear that, The Shelly account is $11.23 more than that in Anne account .

Step-by-step explanation:

Given as :

For Anne

The amount deposited in account = p = $500

The rate of interest = r = 6%  at simple interest

The time period of deposit = t = 4 years

Let The amount received in account after 4 years = $A_1

<u>From Simple Interest method</u>

Simple Interest = \dfrac{\textrm principal\times \textrm rate\times \textrm time}{100}

Or, s.i = \dfrac{\textrm p\times \textrm r\times \textrm t}{100}

Or, s.i = \dfrac{\textrm 500\times \textrm 6\times \textrm 4}{100}

Or, s.i = \dfrac{12000}{100}

i.e s.i = $120

∵ Amount = Principal + Interest

Or, A_1 = p + s.i

Or A_1 = $500 + $120

Or, Amount = $620

So, The Amount in Anne account after 4 years is $620

Again

For, Shelly

The amount deposited in account = P = $500

The rate of interest = R = 6% compounded annually

The time period of deposit = T = 4 years

Let The amount received in account after 4 years = $A_2

<u>From Compound Interest method</u>

Amount = Principal × (1+\dfrac{\textrm rate}{100})^{\textrm time}

Or, A_2 = P × (1+\dfrac{\textrm R}{100})^{\textrm T}

Or, A_2 = $500 × (1+\dfrac{\textrm 6}{100})^{\textrm 4}

Or, A_2 = $500 × (1.06)^{4}

Or, A_2 = $500 × 1.26247

Or, A_2 = $631.23

So, The amount received by Shelly in her account after 4 years = $631.23

Now, Difference between amount received in their account

i.e  A_2 -  A_1 = $631.23 - $620

Or, A_2 -  A_1 = $11.23

Hence, It is clear that, The Shelly account is $11.23 more than that in Anne account . Answer

8 0
3 years ago
Could you help please i dont get it
Akimi4 [234]
Answer should be 39.69 because they all payed 13.23, right? so you add 13.23 together 3 times and get ur answer
6 0
3 years ago
Find the diagonal of a square whose sides are of the given measure.<br><br> Given =
Contact [7]

Answer:

7\sqrt{42}

Step-by-step explanation:

The diagonal is the hypotenuse of the right triangle with legs 7\sqrt{3}

Use Pythagoras' identity to solve for the diagonal d

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

d² = (7\sqrt{3})² + (7\sqrt{3})²

    = 147 + 147

    = 294 ( take the square root of both sides )

d = \sqrt{294} = 7\sqrt{42} ≈ 45.37 ( to 2 dec. places )

6 0
3 years ago
An optical inspection system is used to distinguish among different part types. The probability of a correct classification of a
Whitepunk [10]

Answer: \mu=2.88\ \&\ \sigma^2=0.115

Step-by-step explanation:

Given : The probability of a correct classification of any part is : p=0.96

sample size : n= 3

The formula to find the mean and variance for binomial distribution is given by :-

\mu=np\\\\\sigma^2=np(1-p)

Let the random variable X denote the number of parts that are correctly classified.

The, for the given situation, we have

\mu=3(0.96)=2.88\\\\\sigma^2=(3)(0.96)(1-0.96)=0.1152\approx0.115

Hence, the mean and variance of X are 2.88 and 0.115 respectively.

4 0
3 years ago
Isabella went into a movie theater and bought 3 drinks and 10 pretzels, costing a total of $54.50. Jason went into the same movi
ruslelena [56]

The price of 1 drink is $ 4 and price of 1 pretzel is $ 4.25

<em><u>Solution:</u></em>

Let d" be the price of 1 drink

Let "p" be the price of 1 pretzel

Given that, Isabella went into a movie theater and bought 3 drinks and 10 pretzels, costing a total of $54.50

<em><u>Therefore, we can frame a equation as,</u></em>

3 x price of 1 drink + 10 x price of 1 pretzel = 54.50

3 \times d + 10 \times p = 54.50

3d + 10p = 54.5 ---------- eqn 1

Jason went into the same movie theater and bought 9 drinks and 5 pretzels, costing a total of $57.25

9 x price of 1 drink + 5 x price of 1 pretzel = 57.25

9 \times d + 5 \times p = 57.25

9d + 5p = 57.25 ---------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

Multiply eqn 1 by 3

9d + 30p = 163.5 ----- eqn 3

<em><u>Subtract eqn 2 from eqn 3</u></em>

9d + 30p = 163.5

9d + 5p = 57.25

( - ) -----------------------

25p = 106.25

p = 4.25

<em><u>Substitute p = 4.25 in eqn 1</u></em>

3d + 10(4.25) = 54.5

3d + 42.5 = 54.5

3d = 54.5 - 42.5

3d = 12

d = 4

Thus price of 1 drink is $ 4 and price of 1 pretzel is $ 4.25

4 0
3 years ago
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