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zhuklara [117]
3 years ago
7

a movie theater has 14 different movies showing. If you want to attend no more than 3 of the movies, how many different combinat

ions of movies can you attend
Mathematics
1 answer:
zvonat [6]3 years ago
5 0
14C3 = 14! / 11!3! 

<span>= 14 x13 x12 / 3x2x1 </span>
<span>= 2184 / 6 </span>
<span>= 364 different combinations </span>

<span>The first movie can be any of 14 </span>
<span>As you have already seen one the second movie can be any of the 13 remaining </span>
<span>As you have already seen two the third movie can be any of the 12 remaining. </span>

<span>Therefore there are 14 x 13 x 12 = 2184 PERMUTATIONS of movies you can see. </span>
<span>However among those 2184 different permutations will be instances where you have watched the same three movies but just in a different order. </span>
<span>eg ET, The Piano, Harry Potter = ET Harry Potter The Piano = The Piano, ET, Harry Potter = The Piano Harry Potter ET = Harry Potter ET The Piano = Harry Potter The Piano ET. </span>
<span>For each set of three films there are 3! or 3x2x1 or SIX different ways they can be arranged in. </span>
<span>Therefore we need to DIVIDE the above 2184 permutations by 6 to get the number of COMBINATIONS of different films that can be watched. </span>
<span>2184 / 6 = 364</span>
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Newborn babies: A study conducted by the Center for Population Economics at the University of Chicago studied the birth weights
Fed [463]

Answer:

a) 615

b) 715

c) 344

Step-by-step explanation:

According to the Question,

  • Given that,  A study conducted by the Center for Population Economics at the University of Chicago studied the birth weights of 732 babies born in New York. The mean weight was 3311 grams with a standard deviation of 860 grams

  • Since the distribution is approximately bell-shaped, we can use the normal distribution and calculate the Z scores for each scenario.

Z = (x - mean)/standard deviation

Now,

For x = 4171,  Z = (4171 - 3311)/860 = 1  

  • P(Z < 1) using Z table for areas for the standard normal distribution, you will get 0.8413.

Next, multiply that by the sample size of 732.

  • Therefore 732(0.8413) = 615.8316, so approximately 615 will weigh less than 4171  

 

  • For part b, use the same method except x is now 1591.    

Z = (1581 - 3311)/860 = -2    

  • P(Z > -2) , using the Z table is 1 - 0.0228 = 0.9772 . Now 732(0.9772) = 715.3104, so approximately 715 will weigh more than 1591.

 

  • For part c, we now need to get two Z scores, one for 3311 and another for 5031.

Z1 = (3311 - 3311)/860 = 0

Z2 = (5031 - 3311)/860= 2  

P(0 ≤ Z ≤ 2) = 0.9772 - 0.5000 = 0.4772

  approximately 47% fall between 0 and 1 standard deviation, so take 0.47 times 732 ⇒ 732×0.47 = 344.

5 0
2 years ago
How can we rewrite 4 - (-9) as an addition problem?
Tomtit [17]

So if my ans was helpful u can follow me.

3 0
3 years ago
Read 2 more answers
Simplify:<br>(ay<br>8<br>6.<br>5x - 25 30 - 6x​
maw [93]

Answer:

-x - 2530

Step-by-step explanation:

5x - 2530 - 6x

5x - 6x = -x

-x - 2530

6 0
3 years ago
Read 2 more answers
(giving brainiest)
Nat2105 [25]

Answer:

B- 24 pints

Step-by-step explanation:

128 x 3= 384 ounces

1 ounce = 0.0625

0.0625 x 384= 24 pints

Hope this helps ^-^

4 0
3 years ago
Find two decimals with a product between 1 and 2
Lemur [1.5K]
Here is a method that makes it seem easier. 
<span>Write down any number between 51 and 59. </span>
<span>For example you might choose 57 = 3*19 </span>
<span>Divide both numbers by 10 and write the answer as </span>
<span>0.3 * 1.9 = 0.57</span>
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