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uranmaximum [27]
3 years ago
8

Hippalectryon

Mathematics
1 answer:
FrozenT [24]3 years ago
8 0
Add the who numbers: 4 + 2 = 6

You are correct, it's C. 6
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0.25 x 84 = what huh what someone please help okay please my gosh also show work
steposvetlana [31]
0.25=25/100=1/4. 1/4×84=84/4=21. The answer is 21
8 0
3 years ago
Which statement is correct using "is equal to" (=)?
marishachu [46]

Answer:

The answer is B.

Step-by-step explanation:

Given that each box has 9 pineapples. So if there are 6 boxes, there will be 54 pineapples :

6 × 9 = 54 pineapples

7 0
3 years ago
Read 2 more answers
Find the area and perimeter of ABC at right. Give approximate (decimal) answers, not exact answers
Sever21 [200]

Answer:

Area of Δ ABC = 21.86 units square

Perimeter of Δ ABC = 24.59 units

Step-by-step explanation:

Given:

In Δ ABC

∠A=45°

∠C=30°

Height of triangle = 4 units.

To find area and perimeter of triangle we need to find the sides of the triangle.

Naming the end point of altitude as 'D'

Given BD\perp AC

For Δ ABD

Since its a right triangle with one angle 45°, it means it is a special 45-45-90 triangle.

The sides of 45-45-90 triangle is given as:

Leg1 =x

Leg2 =x

Hypotenuse =x\sqrt2

where x is any positive number

We are given BD(Leg 1)=4

∴ AD(Leg2)=4

∴ AB (hypotenuse) =4\sqrt2=5.66  

For Δ CBD

Since its a right triangle with one angle 30°, it means it is a special 30-60-90 triangle.

The sides of 30-60-90 triangle is given as:

Leg1(side opposite 30° angle) =x

Leg2(side opposite 60° angle) =x\sqrt3

Hypotenuse =2x

where x is any positive number

We are given BD(Leg 1)=4

∴ CD(Leg2) =4\sqrt3=6.93

∴ BC (hypotenuse) =2\times 4=8  

Length of side AC is given as sum of segments AD and CD

AC=AD+CD=4+6.93=10.93

Perimeter of Δ ABC= Sum of sides of triangle

⇒ AB+BC+AC

⇒ 5.66+8+10.93

⇒ 24.59 units

Area of Δ ABC = \frac{1}{2}\times base\times height

⇒  \frac{1}{2}\times 10.93\times 4

⇒ 21.86 units square

5 0
3 years ago
Which is equivalent to log2n=4?
serg [7]

Answer:n=5000

Step-by-step explanation:

if that’s wrong I’m sorry

7 0
3 years ago
Read 2 more answers
A building inspector believes that the percentage of new construction with serious code violations may be even greater than the
Y_Kistochka [10]

Answer:

The inspector's claim has strong statistical evidence.

Step-by-step explanation:

To answer this we have to perform a hypothesis test.

The inspector claimed that the actual proportion of code violations is greater than 0.07, so the null and alternative hypothesis are:

H_0: \pi\leq0.07\\\\H_a: \pi>0.07

We assume a significance level of 0.05.

The sample size is 200 and the proportion of the sample is:

p=\frac{23}{200}= 0.115

The standard deviation is

\sigma=\sqrt{\frac{\pi(1-\pi)}{N} }= \sqrt{\frac{0.07*0.93}{200}}=0.018

The z-value can be calculated as

z=\frac{p-\pi-0.5/N}{\sigma} =\frac{0.115-0.07-0.5/200}{0.018} =\frac{0.0425}{0.018}=2.36

The P-value for this z-value is P=0.00914.

This P-value is smaller than the significance level, so the effect is significant and the null hypothesis is rejected.

The inspector's claim has strong statistical evidence.

7 0
3 years ago
Read 2 more answers
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