S(t) = sin(πt/6) + cos(πt/6)
Velocity = s'(t) = π/6 (cos(πt/6) - sin(πt/6))
When velocity = 0
cos(πt/6) - sin(πt/6) = 0
cos^2(πt/6) -2cos(πt/6) sin(πt/6) + sin^2(πt/6) = 0
1 - 2cos(πt/6) sin(πt/6) = 0
1 - sin(πt/3) = 0
sin(πt/3) = 1
πt/3 = arcsin(1) = π/2
t = 1.5
acceleration = s''(t) = -(π/6)^2 (cos(πt/6) + sin(πt/6))
s''(1.5) = -(π/6)^2 (cos(π/4) + sin(π/4)) = -(π/6)^2 (2/√2) = -0.3877
accerelation = -0.3877 meter/s^2
A real numbers are numbers that can be found on a number line, they include both rational and irrational numbers.
We can first solve the equation;
x² - 6x + 9 =0, using completing square method;
x²- 6x + (-3)² = -9 + (-3)²
(x-3)² = 0
x = 3
therefore, both values of x are 3, thus the expression has no real number x is negative.
The answer is B djiekljfjroeo
It would surely be helpful if you let us know which angles to measure!
