3.4 is 20% of what number? A. 6.8 B. 17 C. 8.5 D. 68

For every 1/150 square mile Xavier mows, Bao mows 1/120 square mile. How many square miles does Xavier mow for every 1 square mi

AlexFokin [52]

I am assuming that it is C. 5/4

8 0

3 years ago

Perry designed the murals by drawing small sketches first. His sketch for a mural measures 5 inches wide by 7 in. tall. If he wa

Harlamova29_29 [7]

Answer:

90

Step-by-step explanation:

5 0

3 years ago

Victor+earns+a+gross+annual+income+of+$84,482+and+is+buying+a+home+for+$185,500. +he+is+making+a+15%+down+payment+and+financing+

Aleks [24]

Answer:

185,500 -.15(185,500)=157,675

Yes he can afford it, it doesn't go over his income and it's %27 below.

4 0

3 years ago

Janet and Marjorie want to buy rolls of material to line rectangular drapes for their rooms. The rectangular piece of material o

Nuetrik [128]

Answer:

They need 2 and 1/2 rolls.

Step-by-step explanation:

Area = length x width

A = l x w

A = 20 x 3

A = 60 ft²

If 60 ft² = 1 roll

What about 150 ft² = ?

= (150 x 1) ÷ 60

= 150 ÷ 60

= 2.5

= 2 and 1/2 rolls

4 0

3 years ago

I need the answer ASAP! Please help me!

masha68 [24]

Answer:

Please check the explanation.

Step-by-step explanation:

Determining the length of BC

From the diagram, it is clear that

The point B is located at (-8, 10) and point C is located at (8, 10)

Since points A and C are located on a horizontal straight line. Thus, the length of BC can be determined by counting the x-axis units from reaching x = -8 to x = 8. i.e. 8-(-8) = 8+8 = 16

Thus, the length of BC = 16 units

Determining the length of CD

Given

C (8, 10)

D (2, -2)

The distance between C(8, 10) and D(2, -2)

$\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$CD=\sqrt{\left(2-8\right)^2+\left(-2-10\right)^2}$

$=\sqrt{6^2+12^2}$

$=\sqrt{36+144}$

$=\sqrt{180}$

$=\sqrt{36\times 5}$

$=6\sqrt{5}$

Thus, the length of CD $=6\sqrt{5}$ units

Determining the length of ED

Given

E (-8, -4)

D (2, -2)

The distance between E(-8, -4) and D(2, -2)

$ED=\sqrt{\left(2-\left(-8\right)\right)^2+\left(-2-\left(-4\right)\right)^2}$

$=\sqrt{10^2+2^2}$

$=\sqrt{100+4}$

$=\sqrt{104}$

$=\sqrt{26\times \:4}$

$=2\sqrt{26}$

Thus, the length of ED $=2\sqrt{26}$ units

Determining the length of EB

From the diagram, it is clear that

The point E is located at (-8, -4) and the point B is located at (-8, 10)

Since points E and B are located on a vertical straight line. Thus, the length of EB can be determined by counting the y-axis units from reaching y = -4 to y = 10. i.e. 10-(-4) = 10+4 = 14

Thus, the length of EB = 14 units

4 0

3 years ago