All categories

4 years ago

How to set up this math problem

Mathematics

1 answer:

e-lub [12.9K]4 years ago

4 0

You can answer this by system of equations:
$x + y = 24 \\ 4x + 5y = 112$
the answer will be

8 candles and 16 soap

good luck

You might be interested in

Five less than half the distance from Delaney’s home to the mall is more than 6 miles.

vovikov84 [41]

let x = the distance from Delany's house to the mall

so half the distance would be 1/2x

then it is 5 miles less than that so you would subtract 5 to give you 1/2x-5

and that is more than 6 miles so you get 1/2x-5>6

5 0

4 years ago

Read 2 more answers

What is the difference in price per kg between chicken sold at $23.24/kg and turkey sold at $5.17/250 g?

Fed [463]

There are 1000 grams in 1 KILOgram.

therefore in 23.24/kg can be just written using grams as 23.24/1000, since 1kg = 1000 g.

so the price of the chicken per gram is then 23.24/1000 or $0.02324 per gram, roughly 2 and 1/3 pennies per gram.

and the turkey is 5.17/250 in grams already, that gives us $0.02068 per gram, which is roughly 2 pennies.

well, their price difference is 0.02324 - 0.02068, which is 0.00256 per gram unit.

since we know there are 1000 grams in 1 Kg, how much is that for 1000 grams or a Kg? 0.00256 * 1000 or $2.56.

8 0

3 years ago

Three more than three times a number is 72. Find the number

puteri [66]

Answer:

Step-by-step explanation:

3x+3=72

3x=72-3

3x=69

x=23

7 0

4 years ago

If 12 cats can catch 6 rats in 2 hours, how many hours would it take 50 cats to catch 75 rats?

sleet_krkn [62]

Answer:

50 cats would take 6 hours to catch 75 rats.

Step-by-step explanation:

After reading the statement we noticed the existence of two relationships:

1) <em>The amount of cats is directly proportional to the quantity of caught rats.</em>

2) <em>The amount of cats is inversely proportional to time taken to catch rats. </em>

That is to say:

$n \propto \frac{x}{y}$

$n = k\cdot \frac{x}{y}$ (Eq. 1)

Where:

$n$ - Amount of cats, dimensionless.

$x$ - Amount of caught rats, dimensionless.

$y$ - Time, measured in hours.

$k$ - Proportionality ratio, measured in hours.

Then, we obtain the following relationship by eliminating the proportionality ratio in (Eq. 1):

$\frac{n_{1}\cdot y_{1}}{x_{1}} = \frac{n_{2}\cdot y_{2}}{x_{2}}$ (Eq. 2)

Where:

$n_{1}$ , $n_{2}$ - Initial and final amounts of cats, dimensionless.

$x_{1}$ , $x_{2}$ - Initial and final amounts of caught rats, dimensionless.

$y_{1}$ , $y_{2}$ - Initial and final times, measured in hours.

Now we clear final time in (Eq. 2):

$y_{2} = y_{1}\cdot \left(\frac{n_{1}}{n_{2}} \right)\cdot \left(\frac{x_{2}}{x_{1}} \right)$

By knowing that $y_{1} = 2\,h$ , $n_{1} = 12$ , $x_{1} = 6$ , $n_{2} = 50$ , $x_{2} = 75$ , then we get that time taken by 50 cats to catch 75 rats is: