Answer: tea = 15 rupees per kg
sugar= 3 rupees per kg
Step-by-step explanation:
Hi, to answer this question we have to write a system of equations with the information given:
<em>"Two kg of tea and 3 kg of sugar cost rupees 39 in january 1997":
</em>
2 t + 3 s =39 (a)
Where:
- t= price of 1 kg of tea
- s = price of 1 kg of sugar
<em>"in march 1997 the price of the tea increased by 25% (1.25)and the price of the sugar increased by 20%(1.20) and the same quantity of tea and sugar cost rupees 48.30.
"</em>
2(t1.25)+3(s1.2) = 48.30 (b)
- <em>Solving for t in (b)
</em>
2t =39-3s
t = (39 -3s)/2
t = 19.5-1.5s
- <em>Replacing the value of t in (b)
</em>
2 x ((19.5-1.5s)1.25)+ 3 ( 1.2s) =48.30
2x ( 24.375 -1.875s) +3.6s =48.30
48.75 -3.75s+3.6s= 48.30
48.75-48.30 = 3.75s-3.6s
0.45= 0.15s
0.45/0.15 =s
3 =s
- <em>Replacing the value of s in (a)
</em>
2 t + 3 (3) =39
2 t + 9 =39
2 t =39 -9
2 t =30
t = 30/2
t= 15
Prices in january:
tea = 15 rupees per kg
sugar= 3 rupees per kg
Feel free to ask for more if needed or if you did not understand something.
Answer:
Step-by-step explanation:
Given
(a): Write as additive inverse.
An additive inverse is of the form a + (-b)
In this case:
So, the expression can be represented as:
(b): Number line representation
When the expression in (a) is solved.
The result is:
This means that the number line must accommodate 7 and -1.
Having said that, options (b) and (c) are out because their range is 0 to 15 and this excludes -1.
Option (d) is a wrong representation of
Hence, (a) is correct
Answer:
3
Step-by-step explanation:
In this expression, the first term is <em>2x</em>, then <em>4y, </em>then 8-2 (which simplifies to 6).
Let
x be the distance that the truck has left to travel
t be the the time
The total distance is 1675 miles
The average speed is 55 miles per hour
The equation that represents the distance that the truck has left to travel with respect to time is
55t + x =1675
x = -55t + 1675
Answer:
Option A
Step-by-step explanation:
2x^2+10x+12
Divide through by 2
x^2 +5x+6=0
x^2 +3x+2x+6
x(x+3)+2(x+3)=0
(x+2)(x+3)=o
x=-2 or x=-3
