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3 years ago

What is the factor of 6a2 – 19a + 10 ???

Mathematics

2 answers:

Dimas [21]3 years ago

8 0

Answer:

(2a - 5) • (3a - 2)

step by step explanation:

Step-1 : Multiply the coefficient of the first term by the constant 6 • 10 = 60

Step-2 : Find two factors of 60 whose sum equals the coefficient of the middle term, which is -19 .

-60 + -1 = -61

-30 + -2 = -32

-20 + -3 = -23

-15 + -4 = -19 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -15 and -4

6a2 - 15a - 4a - 10

Step-4 : Add up the first 2 terms, pulling out like factors :

3a • (2a-5)

Add up the last 2 terms, pulling out common factors :

2 • (2a-5)

Step-5 : Add up the four terms of step 4 :

(3a-2) • (2a-5)

Which is the desired factorization

Final result :

(2a - 5) • (3a - 2)

monitta3 years ago

7 0

Answer:

<h2>(2a-5) (3a-2) is your correct answer.</h2>

thank you ☺️☺️

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mariarad [96]

Answer:

$p_v =P(z>2.087) =0.0184$

So with the p value obtained and using the significance level given $\alpha=0.01$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 1% of significance the mean for the control group it's not significantly higher than the mean of the treatment group by 1 point.

Step-by-step explanation:

When we have two independent samples from two normal distributions with equal variances we are assuming that

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

$\sigma=2.5$

And the statistic is given by this formula:

$z=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sigma\sqrt{\frac{1}{n_1}}+\frac{1}{n_2}}$

Where z follows a normal standard distribution

The system of hypothesis on this case are:

Null hypothesis: $\mu_c \leq \mu_t+1$

Alternative hypothesis: $\mu_c >\mu_t+1$

Or equivalently:

Null hypothesis: $\mu_c - \mu_t \leq 1$

Alternative hypothesis: $\mu_c-\mu_t>1$

Our notation on this case :

$n_c =45$ represent the sample size for group control

$n_t =45$ represent the sample size for group treatment

$\bar X_c =5.2$ represent the sample mean for the group control

$\bar X_t =3.1$ represent the sample mean for the group treatment

And now we can calculate the statistic:

$z=\frac{(5.2-3.1)-(1)}{2.5\sqrt{\frac{1}{45}}+\frac{1}{45}}=2.087$

And now we can calculate the p value using the alternative hypothesis:

$p_v =P(z>2.087) =0.0184$

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4 years ago

2x+7=12x-6 looking for x

Rzqust [24]

Hey!

Let's start by writing the problem:
$2x+7=12x-6$
Subtract 7 from both sides.
$2x+7-7=12x-6-7$
$2x=12x-13$
Subtact 12x from both sides.
$2x-12x=12x-13-12x$
$-10x=-13$
Divide both sides by -10.
$\frac{-10x}{-10}=\frac{-13}{-10}$
$x=\frac{13}{10}$

Let me know if you have any questions regarding this problem!
Thanks!
-TetraFish

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Step-by-step explanation:

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