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4 years ago

Please I need help ASAP

Mathematics

1 answer:

AVprozaik [17]4 years ago

4 0

Answer:

I think it is 26%

Step-by-step 124 divided by 479

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Someone please explain transforming liner equations for me and help me with this question.

PilotLPTM [1.2K]

Sorry hope you find the answer that you’re looking for I am not much help

7 0

3 years ago

Complete parts a through c for the given function.

victus00 [196]

Answer:

a. The critcal points are at

$x=0,-5,3$

b. Then, $x = -5$ is a maximum and $x=3$ is a minimum

c. The absolute minimum is at $x = 3$ and the absolute maximum is at $x = -5.$

Step-by-step explanation:

(a)

Remember that you need to find the points where

$f'(x)=0$

Therefore you have to solve this equation.

$20x^4 + 40x^3 - 300x^2 = 0$

From that equation you can factor out $20x^2$ and you would get

$20x^2 ( x^2 +2x - 15) = 0$

And from that you would have $20x^2 = 0$ , so $x = 0$ .

And you would also have $x^2 +2x-15 = 0$ .

You can factor that equation as $x^2 +2x -15 = (x+5)(x-3) = 0$

Therefore $x=-5 , x=3$ .

So the critcal points are at

$x=0,-5,3$

Remember that a function has a maximum at a critical point if the second derivative at that point is negative. Since

$f''(x) = 80x^3 + 120x^2 -600x\\f''(-5) = 80(-5)^3 + 120(-5)^2 -600(-5) = -4000 < 0\\\\f''(3) = 80(3)^3 + 120(3)^2 -600(3) = 1440 > 0 \\$

Then, $x = -5$ is a maximum and $x=3$ is a minimum

The absolute minimum is at $x = 3$ and the absolute maximum is at $x = -5.$

6 0

3 years ago

Read 2 more answers

What is 100,789,388,369,012 times 479,000,000

8_murik_8 [283]

Answer:

4.8278117e+22

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

A map is laid out in the standard (x,y) coordinate plane. How long, in units, is an airplane's path on the map as the airplane f

xeze [42]

Answer:

Distance between the points A and B is 15.52 units.

Step-by-step explanation:

It has been given in the question that an airplane flies along a straight line from City A to City B.

Map has been laid out in the (x, y) coordinate plane and the coordinates of these cities are A(20, 14) and B(5, 10).

Distance between two points A'(x, y) and B'(x', y') is represented by the formula,

d = $\sqrt{(x-x')^{2}+(y-y')^{2}}$

So we plug in the values of (x, y) and (x', y') in the formula,

d = $\sqrt{(20-5)^{2}+(14-10)^{2}}$

d = $\sqrt{(15)^{2}+(4)^{2}}$

d = $\sqrt{225+16}$

d = 15.52

Therefore, distance between the points A and B is 15.52 units.

4 0

3 years ago

Classify the model as exponential growth or exponential decay. Identify the growth or decay factor AND the percent of increase o

MArishka [77]

See also brainly.com/question/8975313

The growth factor is 1.05.

The increase is (1.05 -1)*100% = 5% per period.

4 0

3 years ago