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Igoryamba
3 years ago
9

The length of Jeff Koon's sculpture is 4 feet more than the width. If the length of the sculpture is 8 feet, what is the area of

the sculpture in square feet?
Mathematics
1 answer:
Mrrafil [7]3 years ago
3 0
(8+4)x8= 96 feet squared

(There is no little 2 to put in so I just wrote squared)
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