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tiny-mole [99]
3 years ago
14

If a fixed number is added to each term of an arithmetic​ sequence, is the resulting sequence an arithmetic​ sequence?

Mathematics
2 answers:
Tom [10]3 years ago
7 0
Yes. But, if the number is multiplied/divided, then it would be a geometrical.
devlian [24]3 years ago
7 0

Answer: Yes, the resulting sequence is an arithmetic sequence.

Step-by-step explanation: Given that a fixed number is added to each term of an arithmetic​ sequence.

We are to check whether the resulting sequence is an arithmetic one or not.

Let the first term of an arithmetic sequence is a and its common difference is d.

Then, the first few terms of the sequence are given by

a,~a+d,~a+2d,~a+3d,~~.~~.~~.

Now, if we add a fixed number k to each term of the sequence, then the sequence will be pf the form :

a+k,~a+d+k,~a+2d+k,~a+3d+k,~~.~~.~~.

Here, we notice that

first term is (a + k) and

(a+d+K)-(a+k)=(a+2d+k)-(a+d+k)=(a+3d+k)-(a+2d+k)=~~.~~.~~.~~=d.

Therefore, the difference between the consecutive terms  in the resulting sequence will also be d.

Thus, the resulting sequence is an arithmetic sequence with first term (a + k) and common difference d.

The answer is YES.

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max2010maxim [7]

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Given Quadratic Equation:  y = 2x2 - 3x + 3

Coefficient Variable Values:  a = 2 and b = -3 and c = 3

Axis of Symmetry:  x = -b/2a = -(-3)/2(2) so answer is x = 3/4

Vertex:  x value is axis of symmetry (3/4) and y value is calculated substituting 3/4 for x in original equation:  y = 2(3/4)2 - 3(3/4) + 3 = 2(9/16) - 9/4 + 3 = 9/8 - 9/4 + 3 = 9/8 - 18/8 + 24/8 = 15/8,
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4 years ago
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krok68 [10]

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