Answer:
41
Step-by-step explanation:
an = a1 + (n-1)d
a_n = the nᵗʰ term in the sequence = 10
a_1 = the first term in the sequence = 5
d = the common difference between terms = 4
a10 = 5 + (10-1)4
a10 = 5 + (9)4
a10 = 5 + 36
a10 = 41
Answer:
The probability that a randomly chosen tree is greater than 140 inches is 0.0228.
Step-by-step explanation:
Given : Cherry trees in a certain orchard have heights that are normally distributed with
inches and
inches.
To find : What is the probability that a randomly chosen tree is greater than 140 inches?
Solution :
Mean -
inches
Standard deviation -
inches
The z-score formula is given by, 
Now,





The Z-score value we get is from the Z-table,


Therefore, the probability that a randomly chosen tree is greater than 140 inches is 0.0228.
Answer:

Option D
Step-by-step explanation:
Given that a producer ships boxes of produce to individual customers.(say x)
X is a normal random variable with mean = 36 and std dev =4 lbs
By definition of std normal variate we know that
is N(0,1)
75th percentile of std normal distribution is
0.675
Hence corresponding x would be

Option D matches with this value
Hence answer is option D
