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love history [14]
3 years ago
13

A 120-watt light bulb uses about 0.1 kilowatt of electricity per hour. If electricity costs $0.20 per kilowatt hour, how much do

es it cost to have the bulb on for an hour?
Mathematics
1 answer:
saveliy_v [14]3 years ago
8 0
There is no such thing as a "kilowatt per hour". If that's actually what the question says, then it's a defective question, and you should put it away before it makes you any more confused. A 120 watt light bulb uses exactly 0.12 kilowatt when it's turned on. In one hour, it uses (0.12 kilowatt) x (1 hour) = 0.12 kilowatt-hour of energy. If energy costs $0.20 per kilowatt-hour, then the cost is (0.12) x (0.20) = 2.4 cents. (0.024 dollar)
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Answer:

(x-1)3

3x-3

Step-by-step explanation:

I came up with this.

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Nolan used the following procedure to find an estimate for StartRoot 18 EndRoot.
stiks02 [169]

Answer:

Nolan correctly identified the square  numbers before and after 18.

The square roots of them are 4 and 5.

Clearly, square root of 18 should lie between 4 and 5 only.

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Since, Nolan is finding estimated square root, his steps are cool and he didn't make any error.

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3 years ago
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Consumer complaints are frequently reported to the Better Business Bureau. Industries with the most complaints to the Better Bus
Licemer1 [7]

Answer:

Let the complaints by Industry be CbI

CbI               Frequency

Bank            26

Cable           44

Car               42

Cell               60

Collection     28

b) Percentages

CbI               percentage (%)

Bank              13

Cable            22

Car                21

Cell               30

Collection     14

c) The industry with the highest number of complaints is the Cell Industry.

d) The Bar Chart is attached to this solution. It was constructed in the Ms Excel suite.

Step-by-step explanation:

a) The frequencies are simply the number of times each industry sector sent in a complaint. So, it's straight forward to present.

b) The percentage for each industry is done in comparison to the the total amount of complaints received.

Percentage for each industry = 100% × (Number of complaints from that industry)/(Total number of complaints)

Total amount of complaints received = 200

For Bank industry,

Percentage = 100% × (26/200) = 13%

For the Cable Industry,

Percentage = 100% × (44/200) = 22%

For Car industry,

Percentage = 100% × (42/200) = 21%

For Cell industry,

Percentage = 100% × (60/200) = 30%

For Collection industry,

Percentage = 100% × (28/200) = 14%

c) The industry with the highest number of complaints is the one with the highest frequency and percentage, and that is the Cell Industry.

d) The Bar Chart is attached to this solution. It was constructed in the Ms Excel suite.

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3 years ago
The local branch of the Internal Revenue Service spent an average of 21 minutes helping each of 10 people prepare their tax retu
AURORKA [14]

Answer:

The confidence Interval is [- 0.7053  10.4521]

a: The  hypotheses  are

H0: μ1=μ2    against the claim Ha :μ1≠μ2

b. The critical value for t∝/2 for 17 d.f  t > 2.508 and  t < -2.111

c. t= -2.8422

d. The calculated value of t= -2.8422 is less than t < -2.11 the critical value therefore we reject H0 and conclude there is a difference between the two means.

Step-by-step explanation:

When the standard deviations are not the same then the confidence intervals for mean differences are calculated as

(x1`-x2`)- t∝/2 √s1²/n1 + s2²/n2 < u1-u2 < (x1`-x2`)+ t∝/2 √s1²/n1 + s2²/n2

x1`= 21        x2`= 27

n1=  10       n2= 14

s1= 5.6       s2= 4.3

The degrees of freedom is calculated using

υ = [s₁²/n1 + s₂²/n2]²/ (s₁²/n1 )²/ n1-1 + (s₂²/n2)²/n2-1

= 17

The t∝/2 for 17 d.f = 2.11

Putting the values

(x1`-x2`)- t∝/2 √s1²/n1 + s2²/n2 < u1-u2 < (x1`-x2`)+ t∝/2 √s1²/n1 + s2²/n2

(21-27) - 2.11√5.6²/10+ 4.3²/14 < u1-u2 <(21-27)  +2.11√5.6²/10+4.3²/14

6- 2.11*2.111 < u1-u2 <  ( 6 )  +2.11*2.111

6- 4.4521 < u1-u2 <  ( 6 )  +5.294

- 1.5479 < u1-u2 <  10.4521

The confidence Interval is [- 0.7053  10.4521]

a: The  hypotheses  are

H0: μ1=μ2    against the claim Ha :μ1≠μ2

The claim is that there is a difference in the average time spent by the two services

b. The critical value for t∝/2 for 17 d.f  t > 2.508 and  t < -2.111

The degrees of freedom is calculated using

υ = [s₁²/n1 + s₂²/n2]²/ (s₁²/n1 )²/ n1-1 + (s₂²/n2)²/n2-1

= 17

c. The test statistic is

t= (x1`-x2`)  /√s1²/n1 + s2²/n2

t= (21-27)  /√5.6²/10+ 4.3²/14

t= -6/2.111

t= -2.8422

d. The calculated value of t= -2.8422 is less than t < -2.11 the critical value therefore we reject H0 and conclude there is a difference between the two means.

5 0
3 years ago
Evaluate the expression. (8 − 5)3 − 24
Amiraneli [1.4K]

Answer:

-15

Step-by-step explanation:

6 0
3 years ago
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