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mash [69]
3 years ago
12

Leah's parents are planning to give her a gift and want to wrap it first. The gift is in a rectangular box with a height of 3 in

ches, a length of 7 inches, and a width of 4 inches. How many square inches of wrapping paper will they need to wrap the gift?
Mathematics
1 answer:
jekas [21]3 years ago
8 0
128 square inches of wrapping paper, since the width would be the Z Axis, That would make a Square 3X4= 12, 12X2= 24. 3X7= 21X4= 104, 104+24=128? That's what I figured. Can you send me a photo of the problem?
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A basketball player scored 288 points in 9 games. Use the unit rate to find how many points the player would score in 5 games.
AysviL [449]

Answer:

160 Points in 5 Games

Step-by-step explanation:

The given information will be used as the first ratio. 288 points / 9 games. To find out how many points this player would score in 5 games, we use another ratio with the unknown value, x. This would be x points / 5 games. Put the ratios equal to each other and cross multiply. You will get a final answer of 160.

3 0
3 years ago
What is an equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 ?
Natali5045456 [20]

Answer:

The equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 is

6x+y=-5

Step-by-step explanation:

Given:  

Let,  

point A( x₁ , y₁) ≡ ( -2 , 7)

To Find:  

Equation of Line  that passes through the point (-2,7) and is perpendicular to the line x-6y=42=?  

Solution:  

x-6y=42    ..................Given

which can be written as

y=mx+c

Where m is the slope of the line

∴ y=\dfrac{x}{6}-7

On Comparing we get

Slope = m = \dfrac{1}{6}

The Required line is Perpendicular to the above line.

So,

Product of slopes = - 1

m\times m_{1}=-1\\Substituting\ m\\ \dfrac{1}{6} m_{1}=-1\\\\m_{1}=-6

Slope of the required line is -6

Equation of a line passing through a points A( x₁ , y₁) and having slope m is given by the formula,  

i.e equation in point - slope form

(y-y_{1})=m(x-x_{1})

Now on substituting the slope and point A( x₁ , y₁) ≡ ( -2, 7) and slope = -6 we get

(y-7)=-6(x--2)=-6(x+2)=-6x-12\\\\\therefore 6x+y=-5.......is\ the required\ equation\ of\ the\ line

The equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 is

6x+y=-5

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