2 years ago

Can someone help me ill give brainles

Mathematics

1 answer:

avanturin [10]2 years ago

6 0

what do you need help with?

You might be interested in

Two motorcyclists start at the same point and travel in opposite directions. One travels 10 mph

aleksandrvk [35]

Answer:

The first is traveling at 51 mph.

The second is traveling at 61 mph.

Step-by-step explanation:

$2(x+ 10) + 2x = 224\\2x + 20 + 2x = 224\\4x + 20 = 224\\4x = 204\\x = 51$

The first is traveling at 51 mph.

The second is traveling at 61 mph.

8 0

2 years ago

Read 2 more answers

How to find a whole number in this question 4% of ... is 56?

Natalka [10]

$\frac{4}{100} * x=56$
$\frac{1}{25} * x=56$
$1400$

8 0

2 years ago

A particle moves on a straight line and has acceleration a(t)=24t+2. Its position at time t=0 is s(0)=3 and its velocity at time

user100 [1]

Answer:

It's position at time t = 5 is 593.

Step-by-step explanation:

The velocity v(t) is the integral of the acceleration a(t)

The position s(t) is the integral of the velocity v(t)

We have that:

The acceleration is:

$a(t) = 24t + 2$

Velocity:

$v(t) = \int {a(t)} \, dt = \int {24t + 2} \, dt = 12t^{2} + 2t + K$

K is the initial velocity, that is v(0). Since V(0) = 13, K = 13

Then

$v(t) = 12t^{2} + 2t + 13$

Position:

$s(t) = \int {s(t)} \, dt = \int {12t^{2} + 2t + 13} \, dt = 4t^{3} + t^{2} + 13t + K$

Since s(0) = 3

$s(t) = 4t^{3} + t^{2} + 13t + 3$

What is its position at time t=5?

This is s(5).

$s(t) = 4t^{3} + t^{2} + 13t + 3$

$s(5) = 4*5^{3} + 5^{2} + 13*5 + 3$

$s(5) = 593$

It's position at time t = 5 is 593.

3 0

2 years ago

What is the answer to the question?

Mumz [18]

Answer:

The answer is 4 zeros

Step-by-step explanation:

(6×5)×10³

30×1000=30000

Therefore 4 zeros in 30000

8 0

3 years ago

Read 2 more answers

What is 3/4 x 2? I tried getting it, but my teacher said it was wrong

Karolina [17]

3/4 x 2/1 = 6/4

Simplify:

6/4 = 3/2

So, 3/2 or 1.5

7 0

2 years ago