Hey there! :)
To find an equation of a line that passes through (5, 1) and has a slope of 2, we'll need to plug our known variables into the slope-intercept equation.
Slope-intercept equation : y = mx + b ; where m=slope, b=y-intercept
Since we're already given the slope, all we really need to do is find the y-intercept.
We can do this by plugging our known values into the slope-intercept equation.
y = mx + b
Since we're trying to find "b," we need to plug in "y, m, x" into our formula.
(1) = (2)(5) + b
Simplify.
1 = 10 + b
Subtract 10 from both sides.
1 - 10 = b
Simplify.
-9 = b
So, our y-intercept is 9!
Now, we can very simply plug our known values into slope-intercept form.
y = mx + b
y = 2x - 9 → final answer
~Hope I helped!~
Answer:
A) y-4=-1/2(x+6)
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(0-4)/(2-(-6))
m=-4/(2+6)
m=-4/8
simplify
m=-1/2
y-y1=m(x-x1)
y-4=-1/2(x-(-6))
y-4=-1/2(x+6)
Answer:
hmm.. very blurry repost please
Step-by-step explanation:
Answer:
a and d
Step-by-step explanation:
If there are 2 pionts on the same VIRTICAL (Upwards and downwards) line, then it is not a function
Answer:
Rephrase that so that x=the number.
3+2x=x
(-2x) => 3=-x
(*-1) => -3=x
Therefore the number is -3!
Step-by-step explanation:
hope this helps :)