Vertex is directly in middle of directix and focus
distance from 8 to -8 is 16
16/2=8
so 8 below focus (since 8>-8) is the point (0,0
vertex is (0,0)
nice
it opens up because focus is above directix
also it goes up down so
4p(y-k)=(x-h)^2
(h,k) is veretx
we got that (h,k) is (0,0)
and p is distance from vertex to focus which is 8
so
4(8)(y-0)=(x-0)^2
32y=x^2
y=(1/32)x^2
(2,-8) (3,-13) because if you plug them all in there the only ones that come out right
Solution: Below! ^^
Detailed explanation:
Hii! I'm sorry, I can't graph the line for you, but I'll try to give you the best possible explanation.
First, note that the question provides us with the info that the y intercept is -8. This is a very valuable piece of information!
This means that the line crosses the y axis (since it's the y intercept) at the point (0,-8). Plot it on the co-ordinate plane.
Next, this question also provides us with the fact that the slope of the line is 1/4. This is yet another valuable piece of information!
What this tells us is: from that point (0,-8), you need to go up 1 unit, then over 4, and so forth, until you obtain a line.
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Hope I helped, best wishes & happy studies!
Please reach out to me if any queries arise.
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