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g100num [7]
3 years ago
9

Two cylinders. The smaller cylinder has height labeled as 6 cm. The larger cylinder has height labeled as 18 cm. The cylinders a

re similar. The volume of the larger cylinder is 40,635 cubic centimeters. What is the volume of the smaller cylinder?
Mathematics
2 answers:
disa [49]3 years ago
6 0
13,545 cm^3 that’s the answer
WITCHER [35]3 years ago
6 0
It would have a volume of 13,545.
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How can 8 ounces be expressed in pounds
Vilka [71]
There are 16 ounces in a pound, so 8 ounces would be half a pound (0.5 lb)
6 0
3 years ago
Read 2 more answers
Solve for x in a right triangle (show work)
AnnZ [28]

Answer:

35.09°

Step-by-step explanation:

You can use cos theta to find the value of x.

Let us solve now.

They have already given the lengths of the hypotenuse and adjacent.

Hypotenuse = 33

Adjacent = 27

Let us solve now.

Cos x = Adjacent ÷ Hypotenuse

Cos x = 27 ÷ 33

Cos x = 0.8181

x = Cos⁻¹ 0.8181

x = 35.09°

Hope this helps you :-)

Let me know if you have any other questions :)

5 0
2 years ago
What is my weighted grade please explain how it's done.
salantis [7]

That's not enough information to calculate your grade from.

-- You've told us the scores you have in things that go together
to make up (35 + 5 + 25) = 65%  of your grade.

-- We don't know your scores in the things that make up the other
35% of your grade.

4 0
3 years ago
Find the coordinates of the midpoint of the line segment with endpoints at ( 6, -7) and (-3,5)
Dmitrij [34]

Answer:

Coordinates of the midpoint are ( 9/2 , -6 )

8 0
2 years ago
If michael jordan has a vertical leap of 1.29 m, then what is his takeoff speed and his hang time
spin [16.1K]
The formula for the vertical height, h, attained with a vertical take off speed of u is
u² - 2gh = 0
where
g = 9.8 m/s², acceleration due to gravity.

Because h = 1.29 m, therefore
u² = 2*9.8*1.39 = 27.244
u = 5.2196 m/s

Also, the time of flight, t, required when the vertical take-off speed is u is given by
ut  - 0.5gt² = 0.
Therefore
5.2196t - 0.5*9.8*t² = 0
5.2196t - 4.9t² = 0
t(5.2196 - 4.9t) = 0
t = 0, or t = 5.2196/4.9 = 1.0652 s

t = 0 corresponds to take-off.
t = 1.0652 s corresponds to landing.
The hang time is 1.0652 s.

Answer:
Take-off speed = 5.22 m/s (nearest hundredth)
Hang time  = 1.065 s (nearest thousandth)

7 0
3 years ago
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