Answer:
Uhh Like 50 different outfits using the same paints and shirts just put differently
Step-by-step explanation:
Answer:
1st picture: (0,4)
The lines intersect at point (0,4).
2nd picture: Graph D
2x ≥ y - 1
2x - 5y ≤ 10
Set these inequalities up in standard form.
y ≤ 2x + 1
-5y ≤ 10 - 2x → y ≥ -2 + 2/5x → y ≥ 2/5x - 2
When you divide by a negative number, you switch the inequality sign.
Now you have:
y ≤ 2x + 1
y ≥ 2/5x - 2
Looking at the graphs, you first want to find the lines that intersect the y-axis at (0, 1) and (0, -2).
In this case, it is all of them.
Next, you would look at the shaded regions.
The first inequality says the values are less than or equal to. So you look for a shaded region below a line. The second inequality says the values are greater than or equal to. So you look for a shaded region above a line.
That would mean Graph B or D.
Then you look at the specific lines. You can see that the lower line is y ≥ 2/5x - 2. You need a shaded region above this line. You can see the above line is y ≤ 2x + 1. You need a shaded region below this line. That is Graph D.
Answer:
Option C.
Step-by-step explanation:
Given information: RSTU is a parallelogram, Digonals RT and SU intersect each other at point V, UV=(x-3) and VS=(3x-13).
According to the properties of a parallelogram, the diagonals of a parallelogram bisect each other.
Using the properties of parallelogram we can say that point V divides the diagonal SU in two equal parts, UV and VS.


Subtract x from both sides.

Add 13 on both sides.

Divide both sides by 2.

Therefore, the correct option is C.
Answer:
Answer : A
Step-by-step explanation:
The given data is 25 th percentile is 64, 50th percentile is 74 and 75 th percentile is 80.
percentage : 25 50 75
score : 64 74 80
Median:- The median is obtained by first arranging the data in ascending or descending order and applying the following rule.
If the number of observations is odd, then the median is observation
term
If the number of observations is even, then the median is observation and observations.

given n=3, middle term is '74'
In this given data the median is (M) = 74
Interquartile range IQR = median of upper half-median of lower half
= 80-64
= 16
IQR = 16
Answer:
$0.90
Step-by-step explanation:

3 dozen = 36

0.4 × y = 36 × 0.1
0.4y = 3.6
0.4y ÷ 0.4 = 3.6 ÷ 0.4
y = 9