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3 years ago

Find the midpoint of a segment with endpoints (-9, 3) and (5, 7). I need help ASAP pleasee

Mathematics

1 answer:

vfiekz [6]3 years ago

8 0

Answer:

( -2,5)

Step-by-step explanation:

To find the x coordinates of the midpoint, add the x coordinates of the endpoint and divide by 2

( -9+5)/2 = -4/2 = -2

To find the y coordinates of the midpoint, add the y coordinates of the endpoint and divide by 2

( 3+7)/2 = 10/2 = 5

The midpoint is ( -2,5)

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Answer:

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Step-by-step explanation:

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3 years ago

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B i think im not sure sorry

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3 years ago

Pls solve the simultaneous equation in the attachment.

siniylev [52]

Answer:

Part a) The solution is the ordered pair (6,10)

Part b) The solutions are the ordered pairs (7,3) and (15,1.4)

Step-by-step explanation:

Part a) we have

$\frac{x}{2}-\frac{y}{5}=1$ ----> equation A

$y-\frac{x}{3}=8$ ----> equation B

Multiply equation A by 10 both sides to remove the fractions

$5x-2y=10$ ----> equation C

isolate the variable y in equation B

$y=\frac{x}{3}+8$ ----> equation D

we have the system of equations

$5x-2y=10$ ----> equation C

$y=\frac{x}{3}+8$ ----> equation D

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substitute equation D in equation C

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$5x-\frac{2x}{3}-16=10$

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$15x-2x-48=30$

$15x-2x=48+30$

Combine like terms

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<em>Find the value of y</em>

$y=\frac{x}{3}+8$

$y=\frac{6}{3}+8$

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The solution is the ordered pair (6,10)

Part b) we have

$xy=21$ ---> equation A

$x+5y=22$ ----> equation B

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$x=22-5y$ ----> equation C

substitute equation C in equation A

$(22-5y)y=21$

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$22y-5y^2=21$

$5y^2-22y+21=0$

Solve the quadratic equation by graphing

The solutions are y=1.4, y=3

see the attached figure

<em>Find the values of x</em>

For y=1.4

$x=22-5(1.4)=15$

For y=3

$x=22-5(3)=7$

therefore

The solutions are the ordered pairs (7,3) and (15,1.4)

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3 years ago

Graph help. how to do the second part of question c

notka56 [123]

Answer:

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Step-by-step explanation:

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2 years ago

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ludmilkaskok [199]

Answer:

yes you are right bro

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Step-by-step explanation:

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3 years ago