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3 years ago

I need a little bit of more help understanding how to do this

Mathematics

1 answer:

taurus [48]3 years ago

3 0

Add 3 to both sides, then add 2m
Then divide 4 on both sides.

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Carla wants the total weight of the bags to be four pounds. If she can only pick one more bag, which bag weight should she pick?

pychu [463]

Answer:

1/8

Step-by-step explanation:

To find which bag weight Carla needs, the first step is to find the total weight of the bags shown in the line plot.

There are three -pound bags.

There are six -pound bags.

There are four -pound bags.

Multiply the weight and number of each bag to find the total weight of each different weight bag.

Now, add the three totals.

Finally, subtract the total weight from four pounds in order to find which weight Carla needs.

So, Carla should pick one -pound bag of candy to total four pounds.

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2 years ago

5y + 4x = 8<br> y + 5x = 10<br> What’s the answer need it nowww

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2 years ago

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fenix001 [56]

Answer:

Step-by-step explanation:

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3 years ago

This box plot shows the heights ( in feet) of a sample of pine trees

kozerog [31]

Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

Michelle's father deposited $1,000 into a savings account when she was born. The annual interest rate is

prohojiy [21]

Answer:

Michelle's age = 16

Step-by-step explanation:

As we know,

Amount = $P (1 + r)^{t}$ where

P = Principal amount

r = rate of interest

t = time

Given ,

P = $1000

r = 4.5 % = $\frac{4.5}{100} = 0.045$

Now,

Given that Amount reaches more than $2000

⇒ $P (1 + r)^{t}$ > 2000

⇒ $1000(1 + 0.045)^{t}$ > 2000

⇒ $(1.045)^{t}$ > 2

Now,

we put the value of t from 0 , 1, 2, ..... untill the above equation does not satisfy

Now,

for t = 0

$(1.045)^{0} = 1 \ngeq 2$

for t = 1

$(1.045)^{1} = 1.045 \ngeq 2$

for t = 2

$(1.045)^{2} = 1.092 \ngeq 2$

for t = 3

$(1.045)^{3} = 1.14 \ngeq 2$

for t = 4

$(1.045)^{4} = 1.19 \ngeq 2$

for t = 5

$(1.045)^{5} = 1.25 \ngeq 2$

for t = 6

$(1.045)^{6} = 1.30 \ngeq 2$

for t = 7

$(1.045)^{7} = 1.36 \ngeq 2$

for t = 8

$(1.045)^{8} = 1.42 \ngeq 2$

for t = 9

$(1.045)^{9} = 1.48 \ngeq 2$

for t = 10

$(1.045)^{10} = 1.55 \ngeq 2$

for t = 11

$(1.045)^{11} = 1.62 \ngeq 2$

for t = 12

$(1.045)^{12} = 1.69 \ngeq 2$

for t = 13

$(1.045)^{13} = 1.77 \ngeq 2$

for t = 14

$(1.045)^{14} = 1.85 \ngeq 2$

for t = 15

$(1.045)^{15} = 1.93 \ngeq 2$

for t = 16

$(1.045)^{16} = 2.02 > 2$

It satisfies at t= 16

∴ we get

Michelle's age = 16

4 0

3 years ago