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MissTica
3 years ago
13

CAN YALL PLS HELP !!!

Mathematics
1 answer:
JulijaS [17]3 years ago
8 0

Answer:

the first step is wrong

it should be 4(x-4)/(x+1)(x-4) - (x+2)/(x-4)(x+1)

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andre [41]

The ball describes a parabola, as you can see in the attached picture. So, the point where the ball strike the ground is the point where the parabola meets the x axis. In fact, the x-axis is the set of points where y=0, which means that the ball has height 0 or -again- it hits the ground.

So, we have to set y=0 in our equation and look for the positive solution. We have

-\dfrac{1}{14}x^2+6x+3=0 \iff x=42\pm\sqrt{1806}

And the positive solution is

42+\sqrt{1806}

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Dmitry runs 3.1 miles on Saturday,shown by the model. He runs 2.45 on Sunday. How much farther does he run on Saturday
Amiraneli [1.4K]

Answer:

0.65 miles.

Step-by-step explanation:

Dmitry runs 3.1 miles on Saturday.

He runs 2.45 miles on Sunday.

On Saturday he runs 3.1 - 2.45 = 0.65 miles farther.

7 0
3 years ago
Read 2 more answers
50 POINTS FIRST GOOD ANSWER GETS BRAINLIEST
Inessa [10]

Answer:

f(x)=3+|2x-5|=\left\{        \begin{array}{ll}            2x-2& \quad x \geq 5/2 \\            -2x+8 & \quad x < 5/2         \end{array}    \right.

Step-by-step explanation:

We are given the function:

f(x)=3+|2x-5|

Remember that by the definition of absolute value:

\displaystyle |x|= \left\{        \begin{array}{ll}            x & \quad x \geq 0 \\        -    x & \quad x < 0        \end{array}    \right.

Our absolute value is:

|2x-5|

First, we will find when it becomes 0. Set the equation equal to 0:

2x-5=0

Solve for <em>x: </em>

<em />x=5/2<em />

<em />

So, we can see that for all values greater than <em>x </em>= 5/2, 2x - 5 is positive.

For all values less than <em>x </em>= 5/2, 2x - 5 is negative.

Therefore (the positive case go above, and the negative case go below):

|2x-5|= \left\{        \begin{array}{ll}            2x-5 & \quad x \geq 5/2 \\           -(2x-5) & \quad x < 5/2         \end{array}    \right.

Finally, we can add a three:

f(x)=3+|2x-5|=\left\{        \begin{array}{ll}            3+(2x-5) & \quad x \geq 5/2 \\            3+(-(2x-5)) & \quad x < 5/2        \end{array}    \right.

Simplify if desired:

f(x)=3+|2x-5|=\left\{        \begin{array}{ll}            2x-2& \quad x \geq 5/2 \\            -2x+8 & \quad x < 5/2         \end{array}    \right.

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arora what u doing on this app? i think u in my classAnswer

Step-by-step explanation:

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