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VLD [36.1K]
3 years ago
13

What is x2-5x+6=0 factorised?

Mathematics
2 answers:
Katyanochek1 [597]3 years ago
8 0
I got 3.2 but i might be wrong
jok3333 [9.3K]3 years ago
3 0
X=3,2 is the answer ...........

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The line plot below shows the weight (in grams) of vitamin bottles.
EleoNora [17]
I cannot answer this because there is no question.
5 0
3 years ago
Find the sum of the positive integers less than 200 which are not multiples of 4 and 7​
taurus [48]

Answer:

12942 is the sum of positive integers between 1 (inclusive) and 199 (inclusive) that are not multiples of 4 and not multiples 7.

Step-by-step explanation:

For an arithmetic series with:

  • a_1 as the first term,
  • a_n as the last term, and
  • d as the common difference,

there would be \displaystyle \left(\frac{a_n - a_1}{d} + 1\right) terms, where as the sum would be \displaystyle \frac{1}{2}\, \displaystyle \underbrace{\left(\frac{a_n - a_1}{d} + 1\right)}_\text{number of terms}\, (a_1 + a_n).

Positive integers between 1 (inclusive) and 199 (inclusive) include:

1,\, 2,\, \dots,\, 199.

The common difference of this arithmetic series is 1. There would be (199 - 1) + 1 = 199 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times ((199 - 1) + 1) \times (1 + 199) = 19900 \end{aligned}.

Similarly, positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 4 include:

4,\, 8,\, \dots,\, 196.

The common difference of this arithmetic series is 4. There would be (196 - 4) / 4 + 1 = 49 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 49 \times (4 + 196) = 4900 \end{aligned}

Positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 7 include:

7,\, 14,\, \dots,\, 196.

The common difference of this arithmetic series is 7. There would be (196 - 7) / 7 + 1 = 28 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 28 \times (7 + 196) = 2842 \end{aligned}

Positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 28 (integers that are both multiples of 4 and multiples of 7) include:

28,\, 56,\, \dots,\, 196.

The common difference of this arithmetic series is 28. There would be (196 - 28) / 28 + 1 = 7 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 7 \times (28 + 196) = 784 \end{aligned}.

The requested sum will be equal to:

  • the sum of all integers from 1 to 199,
  • minus the sum of all integer multiples of 4 between 1\! and 199\!, and the sum integer multiples of 7 between 1 and 199,
  • plus the sum of all integer multiples of 28 between 1 and 199- these numbers were subtracted twice in the previous step and should be added back to the sum once.

That is:

19900 - 4900 - 2842 + 784 = 12942.

8 0
3 years ago
How do I give brainliest I forgot whoever lets me know how I will give them it
dedylja [7]
You have two people answer and whoever answer you think is better you can mark them as brainliest
3 0
2 years ago
In ΔGHI, the measure of ∠I=90°, the measure of ∠G=46°, and IG = 87 feet. Find the length of GH to the nearest tenth of a foot.
sergij07 [2.7K]

Answer:

See attached

I got an answer of 125.2411251548

or to the nearest tenth 125.2

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Which of the following is not a correct way to represent the ratio 5 to 2 a)2/5 c)5:2 b)5/2 d) 10:4
lianna [129]

Answer:

A

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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