Question

Chord AC intersects chord BD at point P in circle Z.

Answer 1

Answer: 5.25 I just took the test!

Step-by-step explanation:

Answer 2

1. To solve this exercise, you must use the "Intersecting chords theorem".

2. You have that:

AP=3.5 in
PC=6 in
DP=4 in

3. Then, by applying the "Intersecting chord theorem", you have:

(AP)(PC)=(BP)(DP)

4. When you substitute the values into (AP)(PC)=(BP)(DP), you obtain:

(3.5 in)(6 in)/BP(4 in)

5. Now, you must clear BP. Then:

(3.5 in)(6 in)/4 in=BP
21 in^2/4 in=BP

6. Therefore, the value of BP is:

BP=5.25 in