Step-by-step explanation:
Hey there!
<u>Firstly </u><u>find </u><u>slope </u><u>of</u><u> the</u><u> </u><u>given</u><u> equation</u><u>.</u>
Given eqaution is: 3x + 2y = 5.......(i)
Now;
![slope(m1) = \frac{ - coeff. \: of \: x}{coeff. \: of \: y}](https://tex.z-dn.net/?f=slope%28m1%29%20%3D%20%20%20%5Cfrac%7B%20-%20coeff.%20%5C%3A%20of%20%5C%3A%20x%7D%7Bcoeff.%20%5C%3A%20of%20%5C%3A%20y%7D%20)
![or \: m1 = \frac{ - 3}{2}](https://tex.z-dn.net/?f=or%20%5C%3A%20m1%20%3D%20%20%5Cfrac%7B%20-%203%7D%7B2%7D%20)
Therefore, slope (m1) = -3/2.
As per the condition of parallel lines,
Slope of the 1st eqaution (m1) = Slope of the 2nd eqaution (m2) = -3/2.
The point is; (-2,-3). From the above solution we know that the slope is (-3/2). So, the eqaution of a line which passes through the point (-2,-3) is;
(y-y1) = m2 (x-x1)
~ Keep all values.
![(y + 3) = \frac{ - 3}{2} (x + 2)](https://tex.z-dn.net/?f=%28y%20%2B%203%29%20%3D%20%20%5Cfrac%7B%20-%20%203%7D%7B2%7D%20%28x%20%2B%202%29)
~ Simplify it.
![2(y + 3) = - 3x - 6](https://tex.z-dn.net/?f=2%28y%20%2B%203%29%20%20%3D%20-%203x%20-%206)
![2y + 6 = - 3x - 6](https://tex.z-dn.net/?f=2y%20%2B%206%20%3D%20%20-%203x%20-%206)
![3x + 2y + 12 = 0](https://tex.z-dn.net/?f=3x%20%20%2B%202y%20%2B%2012%20%3D%200)
Therefore, the eqaution of the line which passes through the point (-2,-3) and parallel to 3x + 2y= 5 is 3x + 2y +12 =0.
<em><u>Hope </u></em><em><u>it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Answer:
c.) 31
Step-by-step explanation:
comment if u need explanation :))
First, you divide the fraction, and then you multiply it by 100.
So you get:
![\frac{5}{16} * 100](https://tex.z-dn.net/?f=%20%5Cfrac%7B5%7D%7B16%7D%20%2A%20100)
![0.3125 * 100](https://tex.z-dn.net/?f=0.3125%20%2A%20100)
![31.25](https://tex.z-dn.net/?f=31.25)
So, 5/16 is 31.25%
Hope this Helps! :)
A.)|−60 − 13| = |−73| = 73 units is the answer
Answer:
(-1,-1)
Step-by-step explanation:
If you multiply the x and y points of A, (-3,-3), by 1/3 then you find: (-1,-1).