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kondaur [170]
3 years ago
14

Answer has to be in degree mode

Mathematics
1 answer:
Marta_Voda [28]3 years ago
6 0

My photo math is saying 59 degrees hope that helps

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Thx for helping if u do
maw [93]

\frac{2}{3}  \div  \frac{1}{8}  =  \frac{2}{3}  \times 8 = 5.33
After rounding off, Answer is 6.

Hope this helps. - M
8 0
3 years ago
Ms. Winter makes homemade bath soaps and bottles of lotion. In her inventory, she has 48 bath soaps and 64 bottles of lotion. Sh
alekssr [168]

first you want to divide both numbers by 16, as the both can divided evenly with that number. you would get the ratio 3:4, which is your answer. ms winter can put 3 bath soaps and 4 bottles of lotion in each basket.

8 0
3 years ago
Urgent! Math help! Answer?
uysha [10]

Answer:

12/13

Step-by-step explanation:

First, use the pythagorean theorem to find EF

5^2 + EF^2 = 13^2

You get: EF = 12

Sin is opposite over hypotenuse. 12 represents the opposite and 13 represents the hypotenuse.

6 0
3 years ago
Sarah kicked a ball in the air. The function
Aleksandr-060686 [28]

Answer: The ball hits the ground at 5 s

Step-by-step explanation:

The question seems incomplete and there is not enough data. However, we can work with the following function to understand this problem:

f=30 t- 6t^{2} (1)

Where f models the height of the ball in meters and t the time.

Now, let's find the time t when the ball Sara kicked hits the ground (this is when f=0 m):

0=30 t- 6t^{2} (2)

Rearranging the equation:

6t^{2}-30 t=0 (3)

Dividing both sides of the equation by 6:

t^{2}-5 t=0 (4)

This quadratic equation can be written in the form at^{2}+bt+c=0, and can be solved with the following formula:  

t=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a} (5)  

Where:  

a=1  

b=-5  

c=0  

Substituting the known values:  

t=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(0)}}{2(1)} (6)  

Solving we have the following result:

t=5 s  This means the ball hit the ground 5 seconds after it was kicked by Sara.

6 0
3 years ago
AB BG, AC GC, ZABC LGBC ZBACZBGC
Naddika [18.5K]

Answer:

Step-by-step explanation:

1) Reflection over \overline{BC}

2) The triangles are congruent by SAS, so when \triangle GBC is mapped onto \triangle ABC, because points G and A are corresponding, G' will correspond with A.

3) Yes, because \overline{BG} \cong \overline{AB}, \overline{GC} \cong \overline{AC}, \angle BAC \cong \angle BGC, so the triangles are congruent by SAS.

7 0
2 years ago
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