Answer:
A
Step-by-step explanation:
Edge
Answer:
6.47secs
Step-by-step explanation:
Given the height of the rocket modelled by the equation;
h = – 16t^2 + 102t + 10, where ‘t' is the time in seconds
The rocket will hit the ground at h = 0
Substitute into the equation
– 16t^2 + 102t + 10 = 0
Multiply through by -1
16t^2-102t-10 = 0
t = 102±√(102)²-4(16)(-10)/2(16)
t = 102±√10404+640/32
t = 102±√11044/32
t = 102 ±105.09/32
t = 102+105.09/32
t = 207.09/32
t = 6.47secs
Hence it will take 6.47secs for the rocket to hit the ground
It is shifted five to the right
Set equal to 0
3=0, nope
3y-12=0
add 12
3y=12
divide 3
y=4
5p-4p-8=-2+3
p-8=1
p=9
1 solution
Answer:
(1,0)(-4,0)
Step-by-step explanation:
