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Andrew [12]
3 years ago
9

Divide the following complex numbers (5i)/(4+3i)

Mathematics
2 answers:
never [62]3 years ago
8 0
To divide these complex numbers you have to multiply by the conjugate of the denominator.  That will look like this:  \frac{5i}{4+3i}* \frac{4-3i}{4-3i}.  Multiply straight across the top and straight across the bottom to get  \frac{20i-15i^2}{16-12i+12i-9i^2}.  In the denominator, the 12i and -12i cancel each other out, which is nice.  Now, in both the numerator and the denominator we have an i-squared.  i-squared is equal to -1, so we will make that substitution in our solution:  \frac{20i-15(-1)}{16-9(-1)}.  Doing the math on that we have  \frac{20i+15}{25}.  We can simplify that as well as write it in standard form:  \frac{15+20i}{25}.  Now we will get it into legit standard form, separating the real part of the complex number from the imaginary part.  \frac{15}{25}+ \frac{20}{25}i.  That can be reduced to its final answer of  \frac{3}{5}+ \frac{4}{5}i.  There you go!
kicyunya [14]3 years ago
5 0

Answer:

17/25 - 19/25 i

Step-by-step explanation:

APEX

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