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irina [24]
3 years ago
13

What is the approximate circumference of a semicircle with a radius of 12 centimeters?

Mathematics
2 answers:
Olenka [21]3 years ago
5 0
Circumference of circle is 2*pi*radius
so 2*3.1416*12 = 75.4 cm
circumference of semicircle would be (1/2) (75.4) = 37.7 cm
answer is 37.7 cm
lisabon 2012 [21]3 years ago
4 0
You do Pi×Radius^2
so 24×Pi=75.4
then 75.4÷2=37.7
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Answer:

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you drop a ball from a height of 98 feet. at the same time, your friend throws a ball upward. the polynomials represent the heig
Ostrovityanka [42]

a) h_0 -u_y t

b) See interpretation below

Step-by-step explanation:

a)

The motion of both balls is a free-fall motion: it means that the ball is acted upon the force of gravity only.

Therefore, this means that the motion of the ball is a uniformly accelerated motion, with constant acceleration equal to the acceleration of gravity:

g=32 ft/s^2

in the downward direction.

For the ball dropped from the initial height of h_0 = 98 ft, the height at time t is given by

h(t) = h_0 -\frac{1}{2}gt^2 (1)

The ball which is thrown upward from the ground instead is fired with an initial vertical velocity u_y, and its starting height is zero, so its position at time t is given by

h'(t)=u_y t - \frac{1}{2}gt^2 (2)

Therefore, the polynomial that represents the distance between the two balls is:

h(t)-h'(t)=h_0 - \frac{1}{2}gt^2 - (u_y t - \frac{1}{2}gt^2) = h_0 -u_y t

b)

Now we interpret this polynomial, which is:

\Delta h(t) = h_0 -u_y t

which represents the distance between the two balls at time t.

The interpretation of the two terms is the following:

- The constant term, h_0, is the initial distance between the two balls, at time t=0 (in fact, the first ball is still at the top of the building, while the second ball is on the ground). For this problem, h_0 = 98 ft

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3 years ago
2)
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Answer:

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Xelga [282]
Carlene needs to sell 480 shirts to meet her goal.
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3 years ago
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The base of a triangle is 1/3 of a foot long and the triangle is 12 feet tall what is the area of the triangle
jok3333 [9.3K]

Answer:

Step-by-step explanation:

Base, b = 1/3

Height, h = 12feet = (12x 0.305)metres = 3.66m

Area of triangle= 1/2 bxh

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Or in feet's

Area of triangle = 1/2 bxh

A = 1/2 x 1/3 x 12 =2 feet^2

5 0
3 years ago
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