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adell [148]
3 years ago
14

Use the data in the table to answer the question. Citations are "speeding tickets." You may fill in the table to help you answer

the question. Original data Line of "best guess" Line of best fit Mph greater than speed limit Number of citations Outputs Residuals Outputs Residuals 5 3 7.5 6 10 10 15 5 20 6 Find the linear approximation of the data that passes through the points (5, 3) and (20, 6).
Mathematics
1 answer:
Vikentia [17]3 years ago
8 0

Answer:

Linear approximation is given by: y = \frac{x}{5}+2

Step-by-step explanation:

We are given the following information in the question:

Number of citations:      5      7.5      10      15       20

 Outputs Residuals:       3       6       10       5          6

We have to find the linear approximation of the data that passes through the points (5, 3) and (20, 6).

Linear approximation is given by:

The equation of line is given by:

(y-y_1) = \displaystyle\frac{y_2-y_2}{x_2-x_1}(x-x_1)

where, (x_1,y_1), (x_2.y_2) is the point through which the line passes.

The equation of line is:

(y-3) = \displaystyle\frac{6-3}{20-5}(x-5)\\\\15(y-3)= 3(x-5)\\15y = 3x-15+45\\15y = 3x + 30\\y = \frac{x}{5}+2

The above equation is the required linear approximation.

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Picture attached, please simplify
Charra [1.4K]
The answer is the second option given
6 0
3 years ago
A researcher conducted a paired sample t-test to determine if advertisements were viewed more in the morning (before noon) or in
Natalija [7]

Answer:

b. No, there was no difference between Morning (M= 32), and Evening (M=40.625), (t [7] = 1.15, p > .05).

Step-by-step explanation:

The critical value for one tailed test is t ∝(7) > 1.895

A one tailed test is performed to test the claim that advertisements were viewed more in the morning (before noon) or in the evening (after 5pm)

The null and alternative hypotheses are

H0: μm = μe   vs     Ha μm > μe

where μm is the mean of the morning and μe is the mean of evening.

The calculated value of t = -1.152587077  which is less than the critical region hence the null hypothesis cannot be rejected .

P(T<=t) one-tail 0.143458126 > 0.05

If two tailed test is performed the critical region is t Critical two-tail 2.364624252

and the calculated t value is  -1.152587077  which again does not lie in the critical region .

Hence μm =  μe or    μm ≤ μe

P(T<=t) two-tail 0.286916252  > 0.025

Therefore

b. No, there was no difference between Morning (M= 32), and Evening (M=40.625), (t [7] = 1.15, p > .05).

Option b gives the best answer.

6 0
3 years ago
What is the slope of the following table?
NNADVOKAT [17]

Answer:

slope: 5/2

Step-by-step explanation:

6 0
3 years ago
$1.85 for a sandwich, $1.15 for a drink, $0.65 for a bag of chips, and $1.10 for two apples. How much money does the student spe
-BARSIC- [3]

Answer:

$4.75 = 4 dollars and 75 cents

Step-by-step explanation:

$1.85 for a sandwich

$1.15 for a drink

$0.65 for a bag of chips

$1.10 for two apples.

The total amount of money the student spent at lunch, in dollars and cents is:

$1.85 + $1.15 + $0.65 + $1.10

= $4.75

In words = 4 dollars and 75 cents

7 0
3 years ago
Read 2 more answers
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