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IceJOKER [234]
3 years ago
8

A baseball team wants a pitcher no more 150 innings during a season. So far, the pitcher has pitched

net/?f=110%20%5Cfrac%7B1%7D%7B4%7D" id="TexFormula1" title="110 \frac{1}{4}" alt="110 \frac{1}{4}" align="absmiddle" class="latex-formula"> innings and has been averaging 5\frac{3}{4} innings per game. At this rate, what is the maximum number of additional games that the pitcher can pitch?
Plz show work and explain .

A. 4
B. 5
C. 6
D.7
Mathematics
1 answer:
butalik [34]3 years ago
5 0

Answer:

C. 6 because any answer besides that is too low or too high.

Step-by-step explanation:

110.25 pitches so far- 150 at max. 5.75 pitches per game.

4: 4x5.75 = 23

110.25 + 23 = 133.25

5. 5x5.75 = 28.75

110.25 + 28.75 = 139

6: 6x5.75 = 34.5

110.25 + 34.5 = 144.75

7: 7x5.75 = 40.25

110.25 + 40.25 = 150.50 > which rounds up to 151

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Let f(x)= x2 - 14 and g(x) = 6-X.<br> Find (fq)(7).
sleet_krkn [62]

Answer:

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Step-by-step explanation:

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and

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(fg)(7)

Note that:

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We substitute the functions to obtain:

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