Answer:
Chet has 14 baseball cards.
Step-by-step explanation:
Ren has 27 cards, which is 13 more than what Chet has. So you subtract. 27-13=14.
Answer:
0.6069
Step-by-step explanation:
Given an approximately normal distribution:
Z = (x - mean) / standard deviation
Mean = 69.3 ; Standard deviation = 2.58
For :
P(x < 70)
Z = (70 - 69.3) / 2.58
Z = 0.7 / 2.58
Z = 0.2713
P(Z < 0.2713) = 0.6069
ANSWER
The area of square ABCD is

EXPLANATION
The area of square ABCD is the square of the length of one side.
That is the area of ABCD is |AD|²
From Pythagoras theorem,

We can read from the graph that, each box is one unit.
This implies that,



Therefore the area of square ABCD is 25 square units.
The correct answer is option C.
Answer:
{-14, 4}
Step-by-step explanation:
the absolute value function only makes sure that the result always has a positive sign.
so, (x + 5) must be either +9 or -9 to make the original equation true. the absolute value would turn both into +9.
so,
x + 5 = 9
x = 4
and
x + 5 = -9
x = -14
that gives us the correct set of solutions as indicated above.
To be honest, I'm not sure which four steps your teacher is referring to. However, I'll show you one way to graph this.
A graph is simply a collection of points. Often those points are connected in some way (though they don't necessarily have to be) to form a curve.
Each point is of the form (x,y). To get each point, we pick random x values and determine their paired y value counterpart.
For example, if we pick x = -3, then,
y= -x^2 -4x -3
y= -(-3)^2 -4(-3) -3
y = -9 - 4(-3) - 3
y = -9 + 12 - 3
y = 0
This indicates that (-3, 0) is one point on the curve.
Let's repeat for x = -2
y= -x^2 -4x -3
y= -(-2)^2 -4(-2) -3
y = -4 - 4(-2) - 3
y = -4 + 8 - 3
y = 1
So (-2, 1) is another point on the curve.
Repeat this process as many times as you want. You should do at least 3 or 4 points in my opinion. The more points you generate, the more accurate the curve. After generating the points, you'll plot them all on the same xy grid. Then finally draw a curve through all of the points as shown below.
I used GeoGebra to make the graph.