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N76 [4]
3 years ago
13

on another training ride Janet box 15 miles in 50 minutes explain how you could find the number of miles she bikes in 1 hour​

Mathematics
1 answer:
Yanka [14]3 years ago
3 0

Answer: 1.2miles

Step-by-step explanation:

Divide 15 by 50 to get how far she rides in 1 minute that multiply that by 60 to get how far she rides in 1 hour.

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Amy’s current grades for her assignments in math class are 85 , 90 , 95 and 80. What grade does she have to earn on her next ass
Lubov Fominskaja [6]

Answer:

100

Step-by-step explanation:

100+90+85+95+80= 450,

450/5=90

5 0
4 years ago
Consider the equation below. (If you need to use -[infinity] or [infinity], enter -INFINITY or INFINITY.)f(x) = 2x3 + 3x2 − 180x
soldier1979 [14.2K]

Answer:

(a) The function is increasing \left(-\infty, -6\right) \cup \left(5, \infty\right) and decreasing \left(-6, 5\right)

(b) The local minimum is x = 5 and the maximum is x = -6

(c) The inflection point is x = -\frac{1}{2}

(d) The function is concave upward on \left(- \frac{1}{2}, \infty\right) and concave downward on \left(-\infty, - \frac{1}{2}\right)

Step-by-step explanation:

(a) To find the intervals where f(x) = 2x^3 + 3x^2 -180x is increasing or decreasing you must:

1. Differentiate the function

\frac{d}{dx}f(x) =\frac{d}{dx}(2x^3 + 3x^2 -180x) \\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'\\\\f'(x)=\frac{d}{dx}\left(2x^3\right)+\frac{d}{dx}\left(3x^2\right)-\frac{d}{dx}\left(180x\right)\\\\f'(x) =6x^2+6x-180

2. Now we want to find the intervals where f'(x) is positive or negative. This is done using critical points, which are the points where f'(x) is either 0 or undefined.

f'(x) =6x^2+6x-180 =0\\\\6x^2+6x-180 = 6\left(x-5\right)\left(x+6\right)=0\\\\x=5,\:x=-6

These points divide the number line into three intervals:

(-\infty,-6), (-6,5), and (5, \infty)

Evaluate f'(x) at each interval to see if it's positive or negative on that interval.

\left\begin{array}{cccc}Interval&x-value&f'(x)&Verdict\\(-\infty,-6)&-7&72&Increasing\\(-6,5)&0&-180&Decreasing\\(5, \infty)&6&72&Increasing\end{array}\right

Therefore f(x) is increasing \left(-\infty, -6\right) \cup \left(5, \infty\right) and decreasing \left(-6, 5\right)

(b) Now that we know the intervals where f(x) increases or decreases, we can find its extremum points. An extremum point would be a point where f(x) is defined and f'(x) changes signs.

We know that:

  • f(x) increases before x = -6, decreases after it, and is defined at x = -6. So f(x) has a relative maximum point at x = -6.
  • f(x) decreases before x = 5, increases after it, and is defined at x = 5. So f(x) has a relative minimum point at x = 5.

(c)-(d) An Inflection Point is where a curve changes from Concave upward to Concave downward (or vice versa).

Concave upward is when the slope increases and concave downward is when the slope decreases.

To find the inflection points of f(x), we need to use the f''(x)

f''(x)=\frac{d}{dx}\left(6x^2+6x-180\right)\\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'\\\\f''(x)=\frac{d}{dx}\left(6x^2\right)+\frac{d}{dx}\left(6x\right)-\frac{d}{dx}\left(180\right)\\\\f''(x) =12x+6

We set f''(x) = 0

f''(x) =12x+6 =0\\\\x=-\frac{1}{2}

Analyzing concavity, we get

\left\begin{array}{cccc}Interval&x-value&f''(x)\\(-\infty,-1/2)&-2&-18\\(-1/2,\infty)&0&6\\\end{array}\right

The function is concave upward on (-1/2,\infty) because the f''(x) > 0 and concave downward on (-\infty,-1/2) because the f''(x) < 0.

f(x) is concave down before x = -\frac{1}{2}, concave up after it. So f(x) has an inflection point at x = -\frac{1}{2}.

7 0
3 years ago
Find the range of each function, given the domain
Olenka [21]
In #12, substitute into the given function the x values {-3, 0, 6} to obtain the range:  the function takes on the following values:  {0, -1, -3}.  Thus, the range for #13 is {0, -1, -3}.

Do the others in precisely the same way.

7 0
4 years ago
A wrestling tournament begins with 128 competitors. In the first round, each competitor has 1 match against another wrestler. Th
Solnce55 [7]
Theres 64 rounds i think that the correct answer
3 0
3 years ago
Read 2 more answers
Henri has $24,000 invested in stocks and bonds. The amount in stocks is $6,000 more than three times the amount in bonds. How mu
kotykmax [81]

Answer:

<u>The amount of investment in bonds is US$ 4,500 and the amount of investment in stocks is US$ 19,500</u>

Step-by-step explanation:

Total investment in stocks and bonds = US$ 24,000

Amount of investment in bonds = x

Amount of investment in stocks = 3x + 6,000 (amount in stocks is $6,000 more than three times the amount in bonds)

For finding the value of x (amount of investment in bonds), we use this equation:

x + 3x + 6,000 = 24,000

x + 3x = 24,000 - 6,000

4x = 18,000

x = 4,500 (dividing by 4)

<u>The amount of investment in bonds is US$ 4,500</u>

Now let's find the amount of investment in stocks:

3x + 6,000 = 3 (4,500) + 6,000 = 13,500 + 6,000 = 19,500

<u>The amount of investment in stocks is US$ 19,500</u>

5 0
4 years ago
Read 2 more answers
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