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natka813 [3]
4 years ago
13

When compared with the energy of an electron in the first shell of a carbon atom, the energy of an electron in the second shell

of a carbon atom is
(1) less(2) greater(3) the same
Chemistry
2 answers:
Alexandra [31]4 years ago
7 0

When compared with the energy of an electron in the first shell of a carbon atom, the energy of an electron in the second shell of a carbon atom is \boxed{\left( {\text{2}} \right){\text{ greater}}}.

Further explanation:

Quantum numbers:

Quantum numbers govern the size, energy, shape, and orientation of an orbital. The four quantum numbers are as follows:

1. Principal Quantum Number (<em>n</em>): It denotes the principle electron shell. The values of n are positive integers (1, 2, 3,…).

2. Angular Momentum Quantum Number (<em>l</em>): It represents the shape of an orbital. The value of l is an integer from 0 to (n-1).

3. Magnetic Quantum Number\left( {{m_l}} \right): This quantum number represents the orientation of the orbital in space. The value of {m_l}lies between –l to +l. The formula to calculate the value of {m_l} is as follows:

{m_l} =  - l,( - l + 1),.....,0,1,2,.....,(l - 1),l

Therefore, the total number of {m_l} values for a given value of l is 2l+1.

4. Electron Spin Quantum Number({m_s}): It represents the direction of the electron spin. Its value can be + \frac{1}{2}or- \frac{1}{2}.

The formula to calculate the energy of an electron in an atom is as follows:

{{\text{E}}_{\text{n}}} = \frac{{ - 13.6{{\text{Z}}^2}}}{{{{\text{n}}^{\text{2}}}}}{\text{eV}}                           …… (1)

Here,

E is the energy of an electron.

Z is the atomic number of atom.

n is the principal quantum number.

Calculation of energy of an electron in the first shell of carbon atom.

The value of Z is 6.

The value of n is 1.

Substitute these values in equation (1) to calculate the energy of electron in the first shell.

\begin{aligned}{{\text{E}}_2}&=\frac{{ - 13.6{{\left( 6 \right)}^2}}}{{{{\left( 1 \right)}^{\text{2}}}}}{\text{eV}}\\&=\boxed{-489.6\;{\text{eV}}}\\\end{aligned}

Calculation of energy of an electron in the second shell of carbon atom.

The value of Z is 6.

The value of n is 2.

Substitute these values in equation (1) to calculate the energy of an electron in the second shell.

\begin{aligned}{{\text{E}}_1}&=\frac{{-13.6{{\left( 6 \right)}^2}}}{{{{\left( 2 \right)}^{\text{2}}}}}{\text{eV}\\&=\boxed{-122.{\text{4 eV}}}\\\end{aligned}

The negative sign in the energy of the electron in both the shells indicates that the electron is bound to the nucleus of an atom. So the energy of electron in the second shell of carbon atom is greater than its energy in the first shell of carbon atom and therefore option (2) is correct.

Learn more:

1. Which transition is associated with the greatest energy change? brainly.com/question/1594022

2. Describe the spectrum of elemental hydrogen gas: brainly.com/question/6255073

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Atomic structure

Keywords: energy of electron, n^2, Z^2, -13.6, n, Z, -122.4 eV, -489.6 eV, 6, 1, 2, first shell, second shell.

erastovalidia [21]4 years ago
6 0
The answer is (2) greater. The energy of an electron will increase when the number of valence shell increases. So the energy of an electron in the second shell of a carbon atom is greater than in the first shell.
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Explanation:

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∴ mol CaI2 = (4.80 E25 units )×(mol/6.022 E23 units) = 79.708  mol CaI2

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WILL GIVE BRAINLIEST - A solution has a [H3O+] of 1 × 10−3 M. What is the [OH−] of the solution?
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Line.
blagie [28]

Answer:

c) Normal

Explanation:

Reflection is a phenomenon typical of light wave; it occurs when a ray of light hits the interface between two mediums, and bounces off back into the original medium, at a certain angle.

The direction of the reflected ray is determined by the law of reflection, which states that:

1) The incident ray and the reflected ray, together with the normal to the interface (the perpendicular to the interface), all lie within the same plane

2) The angle of incidence is equal to the angle of reflection:

\theta_i=\theta_r

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\theta_i is measured as the angle between the incident ray and the normal to the interface

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8 0
3 years ago
To what volume (in mL) would you need to dilute 25.0mL of a 1.45 m solution of Kcl to make a 0.0245m solution of KCl
dezoksy [38]

Answer:

The answer is

<h2>1479.60 mL</h2>

Explanation:

In order to calculate the volume needed we use the formula

V_2 =  \frac{C_1V_1}{C_2}

where

C1 is the concentration of the stock solution

V1 is the volume of the stock solution

C2 is the concentration of the diluted solution

V2 is the volume of thevdiluted solution

From the question

C1 = 1.45 M

V1 = 25 mL

C2 = 0.0245 M

So we have

V_2 =  \frac{1.45 \times 25}{0.0245}   =  \frac{36.25}{0.0245}  \\  = 1479.59...

We have the final answer as

<h3>1479.60 mL</h3>

Hope this helps you

4 0
3 years ago
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