Answer:
Last option C(s) + O2(g) → CO2(g)
Explanation:
The reactions are:
2Ca(s) + Cl2(g) → CaCl2(s)
4Mg(s) + O2(g) → 2MgO(s)
Li(s) + Cl2(g) → 2LiCl(s)
C(s) + O2(g) → CO2(g)
Let's count the atoms (check out the stoichiometry):
1. We have 2 Ca in reactant side and 2Cl, in product side we have 1 Ca and 2 Cl. UNBALANCED
2. We have 4 Mg in reactant side and 2 O. In product side we have 2 Mg and 2 O. UNBALANCED
3. In reactant side we have 1 Li and 2 Cl. Then, in product side we have 2Li and 2Cl. UNBALANCED
C(s) + O2(g) → CO2(g)
1 C and 2 O ⇒ 1 C and 2 O Correctly balanced
Answer:
Image result for How do solute concentrations affect the rate of osmosis within the cell?
Concentration gradient - The movement of osmosis is affected by the concentration gradient; the lower the concentration of the solute within a solvent, the faster osmosis will occur in that solvent.
I think this is it^^^
Explanation:
Answer:
4560 Torr
Explanation:
<u>Boyle's Law</u>
![\sf P_1 \cdot V_1=P_2 \cdot V_2](https://tex.z-dn.net/?f=%5Csf%20P_1%20%5Ccdot%20V_1%3DP_2%20%5Ccdot%20V_2)
where:
= initial volume
= final volume
= initial pressure
= final pressure
Given:
Substituting the given values into the formula:
![\implies \sf 1.5 \cdot 4=P_2 \cdot 1](https://tex.z-dn.net/?f=%5Cimplies%20%5Csf%201.5%20%5Ccdot%204%3DP_2%20%5Ccdot%201)
![\implies \sf P_2=6\:atm](https://tex.z-dn.net/?f=%5Cimplies%20%5Csf%20P_2%3D6%5C%3Aatm)
To convert atm to Torr, multiply atm by 760:
![\implies \sf P_2=6\cdot 760=4560\:Torr](https://tex.z-dn.net/?f=%5Cimplies%20%5Csf%20P_2%3D6%5Ccdot%20760%3D4560%5C%3ATorr)
Hey there!:
Molar mass H3PO4 = <span>97.9952 g/mol
Atomic Masses :
H = </span><span>1.00794 a.m.u
</span>P = <span>30.973762 a.m.u
</span>O = 15.9994 a.m.u<span>
H % = [ ( 1.00794 * 3 ) / </span> 97.9952 ] * 100
H% = <span>3.0857 %
P % = [ ( </span>30.973762 * 1 ) / 97.9952 ] * 100
P% = <span>31.6074 %
O % = [ ( </span>15.9994 * 4 ) / 97.9952 ] * 100
O% = <span>65.3069 %
Hope this helps!</span>