Question

To what volume (in mL) would you need to dilute 25.0mL of a 1.45 m solution of Kcl to make a 0.0245m solution of KCl

Answer 1

Answer:

The answer is

1479.60 mL

Explanation:

In order to calculate the volume needed we use the formula

$V_2 = \frac{C_1V_1}{C_2}$

where

C1 is the concentration of the stock solution

V1 is the volume of the stock solution

C2 is the concentration of the diluted solution

V2 is the volume of thevdiluted solution

From the question

C1 = 1.45 M

V1 = 25 mL

C2 = 0.0245 M

So we have

$V_2 = \frac{1.45 \times 25}{0.0245} = \frac{36.25}{0.0245} \\ = 1479.59...$

We have the final answer as

1479.60 mL

Hope this helps you