Answer:

Step-by-step explanation:

Expanding brackets.

Adding 2m and 6 to both sides.

Combining like terms.

Dividing both sides by 14.

Answer:
1-9 answers
Step-by-step explanation:
1=-38
2=-25
3=16
4=-4
5=0
6=-34
7=9
8=-7
9=-4
<u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u><u>:</u><u> </u>√15 units
Step-by-step explanation:
Let (6,1) be (x^1,y^1) and (1,-9) be (x^2,y^2) .
As we know ,
Distance(D) = √(x^1-x^2) +(y^1-y^2)
Now,
D= √(x^1-x^2) +(y^1-y^2)
= √(6-1) +(1+9)
= √5+10
= √15 units
: Therefore the distance between (6,1) and (1,-9) is √15 units.
Answer:

Step-by-step explanation:
<u><em>The picture of the question in the attached figure</em></u>
we know that
The perimeter of a triangle is the sum of the length of their three sides
so

where
a,b,c are the length sides of the triangle
In this problem we have

substitute and solve for the missing length

After 300 miles.
35+0.1x= 25+0.15x
<u> -0.1x -.01x</u> (0.1- 0.1 crosses out)
35= 25+0.15x
<u> -25 -25 </u> (25- 25 crosses out)
15= 0.15x
15/0.15= 0.15x/0.15 (crosses out)
300= x