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3 years ago

Which line is parallel to y= = 1/3x + 7?

Mathematics

2 answers:

Monica [59]3 years ago

8 0

The answer is the third choic, or the line with the same slope.

N76 [4]3 years ago

6 0

Parallel has same slope = 1/3

so answer is
y = 1/3x - 5 (third option)

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2 years ago

What is 8/12 + A/12=2/b

il63 [147K]

Answer:

the answer i got was a=−8b+24/b

Step-by-step explanation:

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8 0

2 years ago

Given that u =< 2,12 >, and z =< -7,5 >

swat32

Using the dot product:

For any vector x, we have

||x|| = √(x • x)

This means that

||w|| = √(w • w)

… = √((u + z) • (u + z))

… = √((u • u) + (u • z) + (z • u) + (z • z))

… = √(||u||² + 2 (u • z) + ||z||²)

We have

u = ⟨2, 12⟩ ⇒ ||u|| = √(2² + 12²) = 2√37

z = ⟨-7, 5⟩ ⇒ ||z|| = √((-7)² + 5²) = √74

u • z = ⟨2, 12⟩ • ⟨-7, 5⟩ = -14 + 60 = 46

and so

||w|| = √((2√37)² + 2•46 + (√74)²)

… = √(4•37 + 2•46 + 74)

… = √314 ≈ 17.720

Alternatively, without mentioning the dot product,

w = u + z = ⟨2, 12⟩ + ⟨-7, 5⟩ = ⟨-5, 17⟩

and so

||w|| = √((-5)² + 17²) = √314 ≈ 17.720

7 0

1 year ago

PLEASE HELP!! I beg of yall

Delicious77 [7]

Answer:oop

Step-by-step explanation:

5 0

2 years ago

Which answer best describes the complex zeros of the polynomial function?

marysya [2.9K]

Answer-

D. The function has one real zero and two nonreal zeros. The graph of the function intersects the x-axis at exactly one location.

Solution-

The given polynomial is,

$f(x)=x^3-x^2+6x-6$

The zeros of the polynomials are,

$\Rightarrow f(x)=0$

$\Rightarrow x^3-x^2+6x-6=0$

$\Rightarrow x^2(x-1)+6(x-1)=0$

$\Rightarrow (x^2+6)(x-1)=0$

$\Rightarrow (x^2+6)=0,(x-1)=0$

$\Rightarrow x=\sqrt{-6},\ x=1$

$\Rightarrow x=1,\ \pm \sqrt6i$

Therefore, this function has only one real zero i.e 1 and two nonreal zeros i.e ±√6i . The graph of the function intersects the x-axis at exactly one location i.e at x = 1

3 0

2 years ago