The median ( Q2 ) divides the data set into two parts, the upper set and the lower set. The lower quartile ( Q1 ) is the median of the lower half, and the upper quartile ( Q3 ) is the median of the upper half. Example: Find Q1 , Q2 , and Q3 for the following data set, and draw a box-and-whisker plot.
<h3>
Answer: 10,080</h3>
Explanation:
There are 8 letters so there are 8! = 8*7*6*5*4*3*2*1 = 40,320 permutations of those letters. However, the letters "O" and "L" show up twice each, so we must divide by 2! = 2*1 = 2 for each instance this happens.
So,
(8!)/(2!*2!) = (40,320)/(2*2) = (40,320)/4 = 10,080
is the number of ways to arrange the letters of "football".
The reason we divide by 2 for each instance of a duplicate letter is because we can't tell the difference between the two "O"s or the two "L"s. If there was a way to distinguish between them, then we wouldnt have to divide by 2.
x represents the number of lawns weeded by Gwen and y represents the number of dogs walked by Fabio.
Gwen charges $12 each time she weeds a yard and Fabio charges $9 each time he walks a dog.
So, for x number of weeds, Gwen earned 12x and for y number of dogs walked, Fabio earned 9y.
They need at least $510 to purchase the new gaming station.
Therefore,
12x + 9y ≥ 510
Also, the number of dog walks that Fabio has scheduled should not be more than twice the number of yards Gwen has scheduled to weed.
Therefore,
y ≤ 2x
Also, Fabio will walk at least 25 dogs.
Therefore,
y ≥ 25
Hence, the constraints are:
12x + 9y ≥ 510
y ≤ 2x
y ≥ 25
Answer:
x=3X 2 + 5x -6
Step-by-step explanation:
3X2 + 5X-6= 3X2 + 5X 6
X=3X2 +5X -6
