Riley adds 45.3 and 3.21 should his sum be greater than or less than 48 tell how you know

2 answers:

7 0

His sum should be more than 48.

I know because if you throw away the decimal pieces
and just add up the whole numbers 45 and 3 ,
right there you would have 48 . So when you include
the decimal pieces, they'll make it even bigger.

Sav [38]3 years ago

7 0

From it saying Riley ADDS you know its subtracting, so add 45.3 and 3.21 together.
Which is 48.51, so it is greater then 48.

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Answer the Blanks:

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Answer:

1. 90°

2. 90°

3. 40°

4. 45°

5. 45°

Step-by-step explanation:

<u>Given:</u> ΔABC,

CD⊥AB,

m∠A=50°,

m∠ACB=85°

<u>Solution:</u>

1. ∠ADC is a right ange, because CD⊥AB, so

$m\angle ADC=90^{\circ}$

2. ∠CDB is a right ange, because CD⊥AB, so

$m\angle CDB=90^{\circ}$

3. Consider triangle ACD. The sum of the measures of all interior angles is always 180°, so

$m\angle A+m\angle ADC+m\angle ACD=180^{\circ}\\ \\50^{\circ}+90^{\circ}+m\angle ACD=180^{\circ}\\ \\m\angle ACD=180^{\circ}-50^{\circ}-90^{\circ}=40^{\circ}$

4. By Angle Addition Postulate,

$m\angle ACD+m\angle BCD=m\angle ACB\\ \\40^{\circ}+m\angle BCD=85^{\circ}\\ \\m\angle BCD=85^{\circ}-40^{\circ}=45^{\circ}$

5. Consider triangle ABC. The sum of the measures of all interior angles is always 180°, so

$m\angle A+m\angle ACB+m\angle B=180^{\circ}\\ \\50^{\circ}+85^{\circ}+m\angle B=180^{\circ}\\ \\m\angle B=180^{\circ}-50^{\circ}-85^{\circ}=45^{\circ}$