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Mars2501 [29]
3 years ago
11

Two equal forces F have resultant of 1.5F .Find the angle between the forces​

Biology
2 answers:
m_a_m_a [10]3 years ago
8 0

Answer:

The angle between the two forces will be "120°".

Explanation:

Given,

The resultant of force = 1.5F

Now,

By using formula for two resultant of two equal forces, we get

R^2=A^2+B^2+2ABCos\theta

On putting the values, we get

⇒  1.5^2=1.5^2+1.5^2+2(1.5)(1.5)Cos\theta

⇒  2.25=2.25+2.25+4.5Cos\theta

⇒  2.25=4.5+4.5Cos\theta

⇒  4.5Cos\theta=2.25-4.5

⇒  4.5Cos\theta=-2.25

⇒  Cos\theta=\frac{-2.25}{4.5}

⇒  Cos\theta=-\frac{1}{2}

⇒  \theta=120^{\circ}

Grace [21]3 years ago
3 0

Answer:

Angle between the forces​ = 82.82 degrees

Explanation:

The resultant force value = 1.5  times of Force F

|R| = |F1| = |F2| =|F|

Where R is the resultant force

R^2 = A^2 + B^2 + 2AB cos X\\(1.5F)^2 = F^2 + F^2 + 2F^2 cos X\\2.25F^2 = 2F^2 + 2F^2 cos X\\

Cos X is the angle between the two forces.

On further simplifying the equation we get

2.25F^2 = 2F^2(1 + cos X)

(1 + cos X) = \frac{2.25F^2}{2F^2} \\(1 + cos X) = \frac{2.25}{2} \\(1 + cos X) = 1.125\\cos X = 1.125 - 1\\Cos X = 0.125\\X  = Cos^{-1}0.125\\

X = 82.82 degrees

Angle between the forces​ = 82.82 degrees

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