Answer:
- 1 bus, 72 vans
- $6960 is the minimum cost
Step-by-step explanation:
A bus costs over $19 per student; a van costs less than $12 per student. The required number of students could be transported by 81 vans, but that requires 81 chaperones.
Since there are only 80, and a bus requires fewer chaperones per student, we can reduce the number of required chaperones to an acceptable level by employing one bus. 1 bus replaces 9 vans, and requires 1 less chaperone than 9 vans.
The minimum cost is 1 bus and 72 vans. That cost is $1200 +72×$80 = $6960.
Answer:
17,500,000 people
Step-by-step explanation:
70% can be rewritten as 0.7 time 25 million
0.7*25,000,000 = 17,500,000
Answer:
A. The next 3 terms are —9, —11, —13
B. The sequence is Arithmetic
C. The sequence has a common difference of —2
Common difference = T2 — T1 or = T3 — T2
=T2 — T1 = —3 —(—1) = —2 or
= T3 — T2 = —5 —(—3) = —2
D. Tn = a + d(n—1)
a = first term = —1
d = Common difference = —2
n = 27
T27 = —1 + —2(27—1)
T27 = —1 + —2(26)
T27 = —1 —52
T27 = —53
See attachment for math work and answer.
X=18 get Photomath it helps
