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DochEvi [55]
3 years ago
14

Expand and simplify (x-6)(x+2)

Mathematics
2 answers:
ch4aika [34]3 years ago
7 0
Apply the FOIL method: <span>(a+b)(c+d)=ac+ad+bc+bd 

</span>x^2+2x-6x-12&#10; 

<span>Simplify
</span>
x^2-4x-12&#10;
maw [93]3 years ago
4 0
I hope this helps you

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Answer:

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When 3010 adults were surveyed in a​ poll, 27​% said that they use the Internet. Is it okay for a newspaper reporter to write th
tamaranim1 [39]

Answer:

Null hypothesis:p=0.25  

Alternative hypothesis:p \neq 0.25

z=2.53

pv=0.0114

So based on the p value obtained and using the significance given \alpha=0.05 we have p_v so we can conclude that we reject the null hypothesis, and we can said that at 5% of significance the proportion of people who says that they use the Internet differs from 0.25 or 25% .  

Step-by-step explanation:

1) Data given and notation

n=3010 represent the random sample taken

X represent the people who says that said that they use the Internet.

\hat p=\frac{X}{106}=0.27 estimated proportion of people who says that said that they use the Internet.

p_o=0.25 is the value that we want to test

\alpha represent the significance level  

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that 50% of people who says that  they would watch one of the television shows.:  

Null hypothesis:p=0.25  

Alternative hypothesis:p \neq 0.25  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.27 -0.25}{\sqrt{\frac{0.25(1-0.25)}{3010}}}=2.53

4) Statistical decision  

P value method or p value approach . "This method consists on determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

We have the significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(z>2.53)=2*(0.0057)=0.0114  

So based on the p value obtained and using the significance given \alpha=0.05 we have p_v so we can conclude that we reject the null hypothesis, and we can said that at 5% of significance the proportion of people who says that they use the Internet differs from 0.25 or 25% .  

3 0
3 years ago
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