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DochEvi [55]
3 years ago
14

Expand and simplify (x-6)(x+2)

Mathematics
2 answers:
ch4aika [34]3 years ago
7 0
Apply the FOIL method: <span>(a+b)(c+d)=ac+ad+bc+bd 

</span>x^2+2x-6x-12&#10; 

<span>Simplify
</span>
x^2-4x-12&#10;
maw [93]3 years ago
4 0
I hope this helps you

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Given the equation 2 Square root of x minus 5 = 2, solve for x and identify if it is an extraneous solution.
leonid [27]
<span>2 square root (x - 5) = 2. 2^2 (x -5) = 2^2. 4(x - 5) = 4. 4x - 20 = 4. 4x = 24. x = 6. This solution is not extraneous, because extraneous solutions emerge from solving the problem but are not actually valid solutions for the initial problem. With rounding, this solution is valid for the initial problem.</span>
8 0
3 years ago
Read 2 more answers
Use the diagram to help you solve the problem.
Harrizon [31]

Answer:

C

Step-by-step explanation:

Just took it

4 0
3 years ago
Find the measure of the indicated angle
Margarita [4]

Answer:

the unknown angle is 88°

Step-by-step explanation:

the exterior angle of a triangle is equal to the sum of the opposite interior angles. Therefore, in the tall triangle, 60 + 40 = 100, meaning the bottom left angle in the small triangle is 100-64=36. And b/c angle sum of a triangle is 180°, 180-36-56=88°

6 0
3 years ago
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Please help with 6 and 7
Maru [420]

Answer:

6a) i- 2hrs 36mins  ii- 3hrs 12mins

b) car A≈ 76.9km/h  car B≈ 62.5km/h

c)------

7a) 35km

b) car A=75km  car B=60km

c) 30km

d) car A≈36mins  car B≈48mins

Step-by-step explanation:

6a) Using the graph follow the lines until they finish then go downwards until you get to the x-axis. The x-axis is going up by 12mins for each square.

b) Using the answer from a, you divide 200km by the time.

For car A 2hrs 36mins becomes 2.6 because 36mins/60mins=0.6

∴ car A: 200/2.6≈ 76.92km/h

For car B 3hrs 12mins becomes 3.2 because 12mins/60mins=0.2

∴ car B: 200/3.2≈ 62.5km/h

7a) Using the graph go down from where the line of car A finished to meet car B. The y-axis is going up by 5km for each square.

b) Starting from the x-axis at 1 hour go upwards to see where you meet the car B line (60km) and car A line(75km). (sorry if that does not really make sense).

c) Difference from car A line to car B:

155km-125km=30km

d) Going across from 50km meet car A line and go down to see it has been travelling for approx. 36mins. Then continue across to car B line, go down to see it reached 50km at approx. 48mins.

Hope this helps.

5 0
3 years ago
What is the y-intercept of a line parallel to y = 3x - 4 that passes through the point (2,3)
MrRa [10]
Y-3=3(x-2)
y-3=3x-6 :-x=0
y-3=0-6
y=-6+3
y=-3
8 0
3 years ago
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