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Veseljchak [2.6K]
3 years ago
11

What is the intercept s of 3x+y=6

Mathematics
2 answers:
Ksivusya [100]3 years ago
7 0
To find the x-intercept, substitute in
0
0
for
y
y
and solve for
x
x
.
3
x
+
(
0
)
=
6
3
x
+
(
0
)
=
6
Solve the equation.
Tap for more steps...
x
=
2
x
=
2
To find the y-intercept, substitute in
0
0
for
x
x
and solve for
y
y
.
3
(
0
)
+
y
=
6
3
(
0
)
+
y
=
6
Simplify the left side.
Tap for more steps...
y
=
6
y
=
6
These are the
x
x
and
y
y
intercepts of the equation
3
x
+
y
=
6
3
x
+
y
=
6
.
x-intercept:
(
2
,
0
)
(
2
,
0
)
y-intercept:
(
0
,
6
)
dybincka [34]3 years ago
4 0
2,0,6 are the intercepts
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rosijanka [135]

Answer:

-1/5

Step-by-step explanation:

let's put the function in slope intercept form (y = mx + b).

x + 5y = 10

y = - (1/5)x + 2

when the function is in slope intercept form, (m) is the rate of change or the slope.

therefore, the rate of change -1/5

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A circle of center (-3 , -2) passes through the points (0 , -6) and (a , 0). Find a. <br> Pls
ZanzabumX [31]

Answer:

It passes through the point (3,4). Given that the center of the circle is the point (0,0). We know that the equation of the circle is given by : (x-a)^2 + (y-b)^2 = r^2 where (a,b) is the center and r is the radius.

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3 years ago
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$13,957 is invested, part at 7% and the rest at 6%. If the interest earned from the amount invested at 7% exceeds the interest e
ch4aika [34]

Answer:

The Amount invested at 7% interest is $12,855

The Amount invested at 6% interest = $1,102  

Step-by-step explanation:

Given as :

The Total money invested = $13,957

Let The money invested at 7% = p_1  = $A

And The money invested at 6% = p_2 = $13957 - $A

Let The interest earn at 7% = I_1

And The interest earn at 6% = I_2

I_1 -  I_2 = $833.73

Let The time period = 1 year

Now,<u> From Simple Interest method</u>

Simple Interest = \dfrac{\textrm principal\times \textrm rate\times \textrm time}{100}

Or,  I_1 = \dfrac{\textrm p_1\times \textrm 7\times \textrm 1}{100}

Or,  I_1 = \dfrac{\textrm A\times \textrm 7\times \textrm 1}{100}

And

I_2 = \dfrac{\textrm p_2\times \textrm 6\times \textrm 1}{100}

Or,  I_2 = \dfrac{\textrm (13,957 - A)\times \textrm 6\times \textrm 1}{100}

∵  I_1 -  I_2 = $833.73

So, \dfrac{\textrm A\times \textrm 7\times \textrm 1}{100} -  \dfrac{\textrm (13,957 - A)\times \textrm 6\times \textrm 1}{100} = $833.73

Or, 7 A - 6 (13,957 - A) = $833.73 × 100

Or, 7 A - $83,742 + 6 A = $83373

Or, 13 A = $83373 + $83742

Or, 13 A = $167,115

∴ A = \dfrac{167115}{13}

i.e A = $12,855

So, The Amount invested at 7% interest = A = $12,855

And The Amount invested at 6% interest = ($13,957 - A) = $13,957 - $12,855

I.e The Amount invested at 6% interest = $1,102

Hence,The Amount invested at 7% interest is $12,855

And The Amount invested at 6% interest = $1,102   . Answer

8 0
3 years ago
3x-4y=0 2x+y=110 no solution
weeeeeb [17]

Answer:

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Step-by-step explanation:

A graphing calculator can show you the solution to this system of equations is (x, y) = (40, 30). That is the point of intersection where the two lines cross.

__

An algebraic solution can be found by using the substitution method. An expression for y can be found using the second equation:

  y = 110 -2x . . . . . . subtract 2x from both sides

Using this in the first equation gives ...

  3x -4(110 -2x) = 0 . . . . substitute for y

  11x = 440 . . . . . . . . . simplify, add 440

  x = 40 . . . . . . . . . . divide by 11

  y = 110 -2(40) = 30

The solution is (x, y) = (40, 30).

5 0
2 years ago
What percent is 88 of 106
Tems11 [23]
What percent is 88 of 106?

88/106

88 ÷ 106 ≈ .83
.83 × 100 = 83
83%

83% is 88 of 106. 
4 0
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