Answer:
7a
Step-by-step explanation:
Answer:

Step-by-step explanation:
Given

Required
Solve
Using sine rule, we have:

This gives:

So, we have:

In radical forms, we have:


Take LCM

Rewrite as:

Hence:

Answer: A
Step-by-step explanation:
Nothing you a bum
Answer:c
Step-by-step explanation:
when you set (x-6) and (x-1) to zero you get 6 and 1
Answer:
c=35 + 25m
Step-by-step explanation:
Sorry, that's all I got