According to a study done by a university student, the probability a randomly selected individual will not cover his or her mou
th when sneezing is 0.267. suppose you sit on a bench in a mall and observe people's habits as they sneeze. (a) what is the probability that among 18 randomly observed individuals exactly 8 do not cover their mouth when sneezing? (b) what is the probability that among 18 randomly observed individuals fewer than 6 do not cover their mouth when sneezing? (c) would you be surprised if, after observing 18 individuals, fewer than half covered their mouth when sneezing? why?
Let X be a discrete binomial random variable. Let p = 0.267 be the probability that a person does not cover his mouth when sneezing. Let n = 18 be the number of independent tests. Let x be the number of successes. So, the probability that the 18 individuals, 8 do not cover their mouth after sneezing will be:
a) P (X = 8) = 18! / (8! * 10!) * ((0.267) ^ 8) * ((1-0.267) ^ (18-8)). P (X = 8) = 0.0506.
b) The probability that between 18 individuals observed at random less than 6 does not cover their mouth is:
P (X = 5) + P (X = 4) + P (X = 3) + P (X = 2) + P (X = 1) + P (X = 0) = 0.6571.
c) If it was surprising, according to the previous calculation, the probability that less than 6 people out of 18 do not cover their mouths is 66%. Which means it's less likely that more than half of people will not cover their mouths when they sneeze.
Since 12oz of ale contains 124 calories, you have to divide 124 by 12 to find how many calories are in 1 oz of ale. then you multiply 10.33 by 10 to find how many calories are in a 10oz glass of ale.
