If you make $10.75 a day, how many hours do u work if u get paid $5.5 per hour?
the answer would be 1.95 hours or you could put at least 2 hours
Answer:
Height of the fighter plane =1.5km=1500 m
Speed of the fighter plane, v=720km/h=200 m/s
Let be the angle with the vertical so that the shell hits the plane. The situation is shown in the given figure.
Muzzle velocity of the gun, u=600 m/s
Time taken by the shell to hit the plane =t
Horizontal distance travelled by the shell =u
x
t
Distance travelled by the plane =vt
The shell hits the plane. Hence, these two distances must be equal.
u
x
t=vt
u Sin θ=v
Sin θ=v/u
=200/600=1/3=0.33
θ=Sin
−1
(0.33)=19.50
In order to avoid being hit by the shell, the pilot must fly the plane at an altitude (H) higher than the maximum height achieved by the shell for any angle of launch.
H
max
=u
2
sin
2
(90−θ)/2g=600
2
/(2×10)=16km
Answer: (B) 189 4 cm3 is the correct answer
Step-by-step explanation:
Id 977 0670 5097
password a1MgvS
Answer:
1) m∠ZAY = 130°
2) m∠ZXY = 65°
3) m∠SVY = 35°
Step-by-step explanation:
1) the arc angle is the measure of the central angle which intercepts it so 130°
2)measure of the inscribed angle is 1/2measure of intercepted Arc so 1/2 of 130° is 65°
3) In this case two chords intersect inside a circle and four angles are formed
Angle Formed by Two Chords is 1/2*(Sum of Intercepted Arcs) so
m∠SVY = 1/2( m arc RX + m arc YS) = 1/2( 15+55) =1/2 * 70 =35°
