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Thepotemich [5.8K]
3 years ago
10

The Energy Information Administration records the price of electricity in the United State each month. In July 2013, the average

price of electricity was 11.92 cents per kilowatt-hour. Suppose that the standard deviation is 2.1 cents per kilowatt-hour. What can you determine about these data by using Chebyshev's Inequality with K=3?
Mathematics
1 answer:
saw5 [17]3 years ago
6 0

Answer:

89% of the time that average price of electricity is expected to be in the interval from 5.62 cents per kw-h to 18.22 cents per kw-h

Step-by-step explanation:

Chebyshev's inequality states that:

When K = 2, 75% of the data is within two standard deviations of the mean

When K = 3, 89% of the data is within 3 standard deviations of the mean

In this problem, we have that:

Mean = 11.92 cents per kw-h

Standard deviation = 2.1 cents per kw-h

What can you determine about these data by using Chebyshev's Inequality with K=3?

3 standard deviations below the mean

11.92 - 3*2.1 = 5.62 cents per kw-h

3 standard deviations above the mean

11.92 + 3*2.1 = 18.22 cents per kw-h

So you can determine that 89% of the time that average price of electricity is expected to be in the interval from 5.62 cents per kw-h to 18.22 cents per kw-h

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Step-by-step explanation:

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A bag of flour weighed 2.25 kilograms 0.725 kilograms are used in a recipe how many kilograms of flour are left
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Hello!

You subtract the amount of flour you started with by the amount you used

2.250 - 0.725 = 1.525

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Hope this helps!
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1) Let f(x)=6x+6/x. Find the open intervals on which f is increasing (decreasing). Then determine the x-coordinates of all relat
brilliants [131]

Answer:

1) increasing on (-∞,-1] ∪ [1,∞), decreasing on [-1,0) ∪ (0,1]

x = -1 is local maximum, x = 1 is local minimum

2) increasing on [1,∞), decreasing on (-∞,0) ∪ (0,1]

x = 1 is absolute minimum

3) increasing on (-∞,0] ∪ [8,∞), decreasing on [0,4) ∪ (4,8]

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4) increasing on [2,∞), decreasing on (-∞,2]

x = 2 is absolute minimum

5) increasing on the interval (0,4/9], decreasing on the interval [4/9,∞)

x = 0 is local minimum, x = 4/9 is absolute maximum

Step-by-step explanation:

To find minima and maxima the of the function, we must take the derivative and equalize it to zero to find the roots.

1) f(x) = 6x + 6/x

f\prime(x) = 6 - 6/x^2 = 0 and x \neq 0

So, the roots are x = -1 and x = 1

The function is increasing on the interval (-∞,-1] ∪ [1,∞)

The function is decreasing on the interval [-1,0) ∪ (0,1]

x = -1 is local maximum, x = 1 is local minimum.

2) f(x)=6-4/x+2/x^2

f\prime(x)=4/x^2-4/x^3=0 and x \neq 0

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The function is decreasing on the interval (-∞,0) ∪ (0,1]

x = 1 is absolute minimum.

3) f(x) = 8x^2/(x-4)

f\prime(x) = (8x^2-64x)/(x-4)^2=0 and x \neq 4

So the roots are x = 0 and x = 8

The function is increasing on the interval (-∞,0] ∪ [8,∞)

The function is decreasing on the interval [0,4) ∪ (4,8]

x = 0 is local maximum, x = 8 is local minimum.

4) f(x)=6(x-2)^{2/3} +4=0

f\prime(x) = 4/(x-2)^{1/3} has no solution and x = 2 is crtitical point.

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x = 2 is absolute minimum.

5) f(x)=8\sqrt x - 6x for x>0

f\prime(x) = (4/\sqrt x)-6 = 0

So the root is x = 4/9

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Answer:

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Step-by-step explanation:

<u><em>Step(i):</em></u>-

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n(MUP) = 20

Given that  the number of teachers who teach mathematics

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<u><em>Step(ii):-</em></u>

By using   n(A∪B) = n(A) + n(B) - n(A∩B)

                n(M∪P) = n(M) +n(P) - n(M∩P)

                20         = 12 + n(P) - 4

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<u><em>Final answer:-</em></u>

The number of teachers who teach  physics   n(P) = 12

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